Why is my system weaker after upgrading?

No, I said the connections are the point of voltage loss in my vehicle. With a capacitor, you are going to have the same voltage drop due to connections, and yet another tenth or so due to heat because of the repeated charging and dissipating of the capacitor.
It's in parallel, so whatever drop you think is there, will only be observed in series. At least 1 connection could be in series but if you're losing tenths at connections you have done something wrong. How hot do you think capacitors get?
How the hell is a capacitor wired in parallel whilst batteries in the same position would be wired in series?
Did I say that? I was demonstrating absurdity with the absurd by showing that if caps cause problems batts HAVE to.

No sir, the amp doesn't need less voltage to make the same power, it needs less amperage to overcome its resistance. Lower the resistance, lower the current draw.
You'd better brush up on what you're talking about here buddy. You just proved yourself wrong with this statement.

Sorry about all the one liner quotes
It's cool

Unfortunately, in the real world current will flow through it even parallel. Electricity does not take the path of least resistance, electricity takes all available paths. The most current will go through the least resistant avenue (in this case the circuit that does not include the cap), but the parallel circuit (including the cap) will in fact, see current. This will cause unnecessary loss both due to erroneous current, and resistive heat which will, in fact, hurt the electrical system. Caps always hinder an electrical current. They don't always hurt said system enough to become an issue.
Brush up on your electronics. Current PROPORTIONALLY takes all paths which you described except you drew the wrong conclusion. In parallel, the resistance will be smaller than the smallest resistor. So if you have 2 resistors in parallel of different values, the lower value has the least resistance, but when you measure the circuit's resistance the value will be smaller than the smallest resistor. So, even though the cap has resistance, so does the wire. The cap will lower the circuit resistance because even though it has SOME it provides and alternate path. You actually disproved your own case here.

 
I already stated this. It is not applicable to your argument. If the voltage of the rest of the circuit is lower than the cap, explain how the cap is hurting anything. it also defeats your argument because if the cap inherently drops voltage at all times it could never be higher than the source. 

I never said the cap drops voltages at all times. I said it drops the voltage when current is flowing through it.
 
I already stated this. It is not applicable to your argument. If the voltage of the rest of the circuit is lower than the cap, explain how the cap is hurting anything. it also defeats your argument because if the cap inherently drops voltage at all times it could never be higher than the source. 

I never said the cap drops voltages at all times. I said it drops the voltage when current is flowing through it.
Which is guaranteed to happen if the alternator and battery bank are insufficient in maintaining voltage with the current draw the amps put on the system. Essentially, if a capacitor sees use in an electrical system, it will tax said system.

 

NH, I won't argue semantics with you over the lesser of the two values for resistance. Agree to disagree on what it proves.

 

but this guys isn't even competing so if he loses .1 voltage drop is ok because hes not competing.. where are you OP? learned anything yet? i havent bro. lol
This entire rabbit trail started because of the argument that it was completely redundant for him to attempt to utilize a capacitor for voltage maintenance and system stability. Both sides (although arguing another issue) have clearly stated it would not serve that purpose well.
 
Which is guaranteed to happen if the alternator and battery bank are insufficient in maintaining voltage with the current draw the amps put on the system. Essentially, if a capacitor sees use in an electrical system, it will tax said system.

NH, I won't argue semantics with you over the lesser of the two values for resistance. Agree to disagree on what it proves.

This entire rabbit trail started because of the argument that it was completely redundant for him to attempt to utilize a capacitor for voltage maintenance and system stability. Both sides (although arguing another issue) have clearly stated it would not serve that purpose well.
definetly isn't getting no where.
 
I upgraded from my 4 gauge to 0 gauge (both power and ground)Upgraded the amp from a md2d (1500 watts) to a sundown saz 2000d

Upgraded my speaker from a fib l to a fi sp4

Added a farad, Rockford Fosgate Rfc10hb 10 Farad Hybrid Digital Capacitor

The only thing I kept the same was the battery and the box, but for some reason its just sounds weaker (the sub is brand new and not even close to being broken in yet)

Before I could shake my front mirror on 4 with not everything turn up, not I got to put it at 8 and have everything turn ed to do the same.

The only thing I can think of is it was wired wrong and not producing 1 ohm, its producing 8 ohms, (it’s a dual 2 ohm sub), or the box isn’t big enough (but it should still be hitting a lot harder then what it is right now), anyone got any ideas on what it could be?
You did a few things right... Except for the capacitor, there's just no point in it, for how you're using it. Since you don't want to invest more into a car you're selling, get an extra battery to put in the back, you need more voltage. Also, do your big 3 if you haven't done that already. Then, make sure your sub is wired to 1 ohm. Also, what is this "setting on 4, then setting on 8" nonsense? Lastly, and probably most importantly, you need a new box.

 
I already stated this. It is not applicable to your argument. If the voltage of the rest of the circuit is lower than the cap, explain how the cap is hurting anything. it also defeats your argument because if the cap inherently drops voltage at all times it could never be higher than the source. 

I never said the cap drops voltages at all times. I said it drops the voltage when current is flowing through it.
 

Since it's in parallel, it can't.
 
Which is guaranteed to happen if the alternator and battery bank are insufficient in maintaining voltage with the current draw the amps put on the system. Essentially, if a capacitor sees use in an electrical system, it will tax said system.
Not at all true. Since it takes a difference of potential for current to flow, and since the capacitor charges up to the circuit voltage it stops drawing current. (WHereas a battery does not so a battery DOES "tax the system") When the voltage drops below the capacitor's voltage, it is now the highest source of potential and begins discharging. It will only draw current once the system voltage comes back up because it's not under as heavy of a load. Then there is a difference of potential and the capacitor can recharge. This proves that a capacitor is not a parasite, but a battery is. You guys have misdiagnosed a situation. That is what this argument is about.

NH, I won't argue semantics with you over the lesser of the two values for resistance. Agree to disagree on what it proves.
Why? It's all verifiable. Someone is wrong here. If people have fact-checked they already know who that is.

 
Since it's in parallel, it can't.
ok this maybe irrelavent but. you haz power cable and you weld it its still in parrell right lol but you are adding more shit in the way of the current flow.. you know what i means. so when you conect the cap in between the bat and amp there you are adding more resistance from the cables getting in the way of the cable; so why make this harder for me you and him n her and them?
 
ok this maybe irrelavent but. you haz power cable and you weld it its still in parrell right lol but you are adding more shit in the way of the current flow.. you know what i means. so when you conect the cap in between the bat and amp there you are adding more resistance from the cables getting in the way of the cable; so why make this harder for me you and him n her and them?
So by your example, if I have a circuit with 1 100 ohm resistor and I add a second resistor in parallel, I am adding resistance?
 
ok this maybe irrelavent but. you haz power cable and you weld it its still in parrell right lol but you are adding more shit in the way of the current flow.. you know what i means. so when you conect the cap in between the bat and amp there you are adding more resistance from the cables getting in the way of the cable; so why make this harder for me you and him n her and them?
So by your example, if I have a circuit with 1 100 ohm resistor and I add a second resistor in parallel, I am adding resistance?
 
thats not what im saying dont try to turn this around. example i have a speaker and add some bolts from subs to box im adding resistance.
So then big banks of batteries drop tons of voltage with their tons of connections? I'm not trying to turn anything around. I'm trying to follow your logic here.
 
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