Gain setting

[Original wis]

The question I have is actually pretty simple I think. If you set your amp gain knob to four volts but the actual voltage going in is 2 volts will that cut the actual output voltage to 50%?

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[winkychevelle 10+ year member]

The question I have is actually pretty simple I think. If you set your amp gain knob to four volts but the actual voltage going in is 2 volts will that cut the actual output voltage to 50%?

It should be assuming the amp was previously set to 4v of clean input signal.

Thus 2v of clean input signal would be half the output voltage

 

[Original wis]

Thanks appreciated. Gonna set amps for components that way. Have an Axxess DSP so signal is clean

 

[winkychevelle 10+ year member]

Thanks appreciated. Gonna set amps for components that way. Have an Axxess DSP so signal is clean

V(ac)=√(watt×ohm)
Use a dmm set to volts ac and this formula.

Make sure your crossovers are set firsts.

1000hz test tone.

 

[Original wis]

V(ac)=√(watt×ohm)
Use a dmm set to volts ac and this formula.

Make sure your crossovers are set firsts.

1000hz test tone.

Does that work if I'm purposely trying to lessen the output voltage to the speakers?

What I want to do is purposely cut the level to the speakers 25 to 75% because the RMS rating for the amps is higher than the recommended RMS for the speakers.

I have a digital multimeter and I'm planning to use it to calculate the correct signal strength for input and output I just wanted to make sure that my logic was correct.

 

[winkychevelle 10+ year member]

Does that work if I'm purposely trying to lessen the output voltage to the speakers?

What I want to do is purposely cut the level to the speakers 25 to 75% because the RMS rating for the amps is higher than the recommended RMS for the speakers.

I have a digital multimeter and I'm planning to use it to calculate the correct signal strength for input and output I just wanted to make sure that my logic was correct.

Yes you can set the gain to whatever watt RMS you want below the amps max output using that formula.