gain set

[DFW40 10+ year member]

What should the voltage be with a eD nine.1

1200 watts @1ohm

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[squeak9798 5,000+ posts]

34.64v

 

[iceteebone 5,000+ posts]

the formula is power (1200) multiplied by impedence (1 ohm) which equals 1200, then find the square root of that number.

 

[nosaj070 10+ year member]

34.64v

//content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif

The amp has no bearing on what the input gain should be set at, its your HU that determines that. Someone will throw a link up here soon enough about how to do it, i'm too lazy to find it.

 

[DFW40 10+ year member]

Thanks guys, I read through the tutorial rather fast but could not find the exact formula.

 

[DFW40 10+ year member]

so for the comps amp

110 by 2 (12.5 volts) at 4 ohms per channel

but my car is about 13.5 volts when volume pumping

so my amp would be putting out around 125 watts a channel at 4 ohms

125 by 4 is 500 and the square root is 22.3

right/ wrong?

 

[Zombietime 10+ year member]

so for the comps amp
110 by 2 (12.5 volts) at 4 ohms per channel

but my car is about 13.5 volts when volume pumping

so my amp would be putting out around 125 watts a channel at 4 ohms

125 by 4 is 500 and the square root is 22.3

right/ wrong?

To figure out the output voltage you need to do this:

Voltage = square root of (Power * Resistance)

So, 500x4 = 2000 - square root of 2000 = 44.72

44.72 is your output voltage

 

[iceteebone 5,000+ posts]

To figure out the output voltage you need to do this:
Voltage = square root of (Power * Resistance)

So, 500x4 = 2000 - square root of 2000 = 44.72

44.72 is your output voltage

his amp is a 2-channel. it would be 125 time 4 which is 500 and then the square root of that number. not sure where you are getting your numbers.

 

[Zombietime 10+ year member]

his amp is a 2-channel. it would be 125 time 4 which is 500 and then the square root of that number. not sure where you are getting your numbers.

You need to account for the ohms. He said his amp is 500 watts at 4 ohms.

 

[iceteebone 5,000+ posts]

You need to account for the ohms. He said his amp is 500 watts at 4 ohms.

he said his amp is 125 watts at 4 ohm which equals 500. //content.invisioncic.com/y282845/emoticons/wink.gif.608e3ea05f1a9f98611af0861652f8fb.gif

 

[Zombietime 10+ year member]

he said his amp is 125 watts at 4 ohm which equals 500. //content.invisioncic.com/y282845/emoticons/wink.gif.608e3ea05f1a9f98611af0861652f8fb.gif

He said 125 watts per channel. 125 x 4 = 500 x 4 ohms = 2000

 

[iceteebone 5,000+ posts]

He said 125 watts per channel. 125 x 4 = 500 x 4 ohms = 2000

it was 125 x2. you should only need to set the gain then on the 1 channel which would be 125 watts rms.

 

[DFW40 10+ year member]

sorry that was confusing

125 X 2 @ 4 ohm

125 watts times 4 ohms is 500 and the square root of that is 22.3

 

[Zombietime 10+ year member]

sorry that was confusing
125 X 2 @ 4 ohm

125 watts times 4 ohms is 500 and the square root of that is 22.3

Oh ok it's 125x2...

125 x 2 = 250

250 x 4 ohms = 1000

square root of 1000 = 31.6

 

[iceteebone 5,000+ posts]

Oh ok it's 125x2...
125 x 2 = 250

250 x 4 ohms = 1000

square root of 1000 = 31.6

you don't multiply the power of both chanels together. when you hook up the dmm to 1 of the speaker outputs, it's only putting out 125 watts not 250 watts. and he's not bridging the amp.