ultimate157
5,000+ posts
Engineering Student
I was just thinking about how I set my filters. The analog knob on most amps are never really that well marked as to where the filter is set (Some only have the min/max values printed)
Electrically speaking, -3db is 1/2 the wattage.
So far my thinking is this: You set your gains correctly with ZERO filters enabled. Play a test tone equal to your desired crossover frequency and record the voltage; This should equal what you set your gains to. Turn on the filter (high or low pass) and adjust to your desired voltage.
Now, you've set your gains to a specific wattage, at a certain impedance, and you've measured the voltage.
Say you set your gains for 150w at 4 ohms. This would come out to 24.49v. If you halve the wattage to 75w at 4 ohms, then the voltage should be 17.32v at 80hz with the filter on and set.
Am I getting to something here ? Discussion?
Electrically speaking, -3db is 1/2 the wattage.
So far my thinking is this: You set your gains correctly with ZERO filters enabled. Play a test tone equal to your desired crossover frequency and record the voltage; This should equal what you set your gains to. Turn on the filter (high or low pass) and adjust to your desired voltage.
Now, you've set your gains to a specific wattage, at a certain impedance, and you've measured the voltage.
Say you set your gains for 150w at 4 ohms. This would come out to 24.49v. If you halve the wattage to 75w at 4 ohms, then the voltage should be 17.32v at 80hz with the filter on and set.
Am I getting to something here ? Discussion?
