Plutoman 10+ year member
<-- Yes, that's me.
It's pretty simple...
You calculate voltages based on the wattage you want to put out into the ohm load. Square root of the watts times the ohm load is the voltage you want.
And ever taken a basic physics class? Wire two ohm loads in parallel - these 8 ohms, for example - 1/8 + 1/8 = 1/4. Take 1 / (1/4) and you get 4 ohms. There's a method for calculating the ohm load for a parallel wiring.
And thirdly, search. An amp, except for some class D low impedance amplifiers, can run at pretty much any impedance above 2 ohms. It just puts out less power. I'm not sure how you'd get 8 ohms out of two 8 ohm subwoofers though. You'd get either 16 or 4.
I think maybe you need to not look at the svc 4 ohm subwoofers when you look at RF's page. And pay attention to what you have.
You calculate voltages based on the wattage you want to put out into the ohm load. Square root of the watts times the ohm load is the voltage you want.
And ever taken a basic physics class? Wire two ohm loads in parallel - these 8 ohms, for example - 1/8 + 1/8 = 1/4. Take 1 / (1/4) and you get 4 ohms. There's a method for calculating the ohm load for a parallel wiring.
And thirdly, search. An amp, except for some class D low impedance amplifiers, can run at pretty much any impedance above 2 ohms. It just puts out less power. I'm not sure how you'd get 8 ohms out of two 8 ohm subwoofers though. You'd get either 16 or 4.
I think maybe you need to not look at the svc 4 ohm subwoofers when you look at RF's page. And pay attention to what you have.