Nosferatu333 10+ year member
Member
Sup fellaz,
I have a q-logic dual 10 inch enclosure that measures .65 cubes per sub. I need it to measure .525 per sub (Boston Pro .5's)
I plan on placing 2x4's cut to length to drop down the cubes. I have already figured out the lengths i need to drop it to the desired size.
My question to you guys is if im correct in my logic.
I used the formula to calculate internal volume: HxWxD divided by 1728. I plugged in deminsions of 2x4's until i obtained the difference between .65 and .525. I plan to add that difference in 2x4's in the enclosure to drop the total cubes.
Is this a sound plan. I know it may sound confusing but if there are clarifying questions please ask.
If im incorrect in my thinking please correct me.
Thanks to all in advance.
I have a q-logic dual 10 inch enclosure that measures .65 cubes per sub. I need it to measure .525 per sub (Boston Pro .5's)
I plan on placing 2x4's cut to length to drop down the cubes. I have already figured out the lengths i need to drop it to the desired size.
My question to you guys is if im correct in my logic.
I used the formula to calculate internal volume: HxWxD divided by 1728. I plugged in deminsions of 2x4's until i obtained the difference between .65 and .525. I plan to add that difference in 2x4's in the enclosure to drop the total cubes.
Is this a sound plan. I know it may sound confusing but if there are clarifying questions please ask.
If im incorrect in my thinking please correct me.
Thanks to all in advance.