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<blockquote data-quote="Nosferatu333" data-source="post: 5626406" data-attributes="member: 588173">Sup fellaz,I have a q-logic dual 10 inch enclosure that measures .65 cubes per sub.&nbsp; I need it to measure .525 per sub (Boston Pro .5&#039;s)I plan on placing 2x4&#039;s cut to length to drop down the cubes. I have already figured out the lengths i need to drop it to the desired size.My question to you guys is if im correct in my logic.I used the formula to calculate internal volume: HxWxD divided by 1728. I plugged in deminsions of 2x4&#039;s until i obtained the difference between .65 and .525. I plan to add that difference in 2x4&#039;s in the enclosure to drop the total cubes.Is this a sound plan.&nbsp; I&nbsp; know it may sound confusing but if there are clarifying questions please ask.If im incorrect in my thinking please correct me.Thanks to all in advance.</blockquote>

[QUOTE="Nosferatu333, post: 5626406, member: 588173"] Sup fellaz, I have a q-logic dual 10 inch enclosure that measures .65 cubes per sub. I need it to measure .525 per sub (Boston Pro .5's) I plan on placing 2x4's cut to length to drop down the cubes. I have already figured out the lengths i need to drop it to the desired size. My question to you guys is if im correct in my logic. I used the formula to calculate internal volume: HxWxD divided by 1728. I plugged in deminsions of 2x4's until i obtained the difference between .65 and .525. I plan to add that difference in 2x4's in the enclosure to drop the total cubes. Is this a sound plan. I know it may sound confusing but if there are clarifying questions please ask. If im incorrect in my thinking please correct me. Thanks to all in advance. [/QUOTE]

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