huh?
ohms law doesnt change, bro.
14.4vdc x 700a x 1 ohm = 10080watts x .8 (typical class d 80% efficiency) ~8065w~ but we'll just go with a nice rounded 8k
rail volt-amperes needed;
square root of: power (watt) multiplied by resistance (ohm)
2000 x 4 = 8000
4000 x 2 = 8000
8000 x 1 = 8000
sq rt of 8000 = 89.4427va
this is the rail volt-amperes needed to sustain 8000w at 1 ohm driven cleanly, or 4k @ 2, 2k @4,.. etc, etc.
the rail va remains constant regardless of load resistance, thus, the current needed to supply said volt-amperes from the dc input will also remain constant unless dc input voltage or gain changes. more input voltage applied requires less current to attain rail voltage and just the inverse. lessening the gain will require less current as you are dropping the output power.