so n so chicago 10+ year member
Member
I got a premanufactured enclosure... WAIT!!! don't shoot
I am still a newbie
Anyhow it is 0.75" MDF, really small though, but it was real cheap...
Anyhow, I am trying to figure out what the internal volume is and the frequency of the box is.
It is one chamber for two 12"s and has a slot port in the middle. I have done TONS of reading and my confusion is still: when making calculations using the box dimensions do I include the width of the slot or completley ignore that part. Also, the slot is made with a particular length (10.5") of 0.75" MDF wood. Is there a formula for how much volume that would take up, i.e. the slots is made of two pieces of wood that are .75" thick, 12.5" tall and the length is 10.5".
i wish I could draw a picture, but like I said it has one slot in the middle.
PRIMARY QUESTION IS:
To measure the internal volume do I exclude the section that makes the slot port, i.e. subtract 0.75" X2 (thickness of both pieces of wood that make the slot port) and subtract the 2.5" that acutally makes the hole from the total width?
FYI, the dimensions are as follows...
outside dimesions of box...
H 14"
W 32"
D 15.5"
Square port (not including the thickness of the wood):
W 2.5
H 12.5
the length is 10.5"
I know the box is really small and probably tuned really high (and therefore will likely sound like crap), but it was cheap and I want to see how it sounds and would still like to be able to figure out the frequency it is at.
all stabs at answering this post are appreciated
Thank you
ps
FYI: I understand generally how to get volume, i.e. in the case of a sealed enclosure.
I know it won't "fix" the lack of size, but I am hoping that polyfill will help if needed once I figure out the numbers. Additionally, I have 2 JL12w6v2s that the manufacturer recommends only 1.5cf for each in a vented enclosure anyhow...
addendum:
will using polyfil increase the tuning (by decreasing volume) or will it actually decrease tuning by its "slowing down of the air effect"?
I am still a newbie
Anyhow it is 0.75" MDF, really small though, but it was real cheap...
Anyhow, I am trying to figure out what the internal volume is and the frequency of the box is.
It is one chamber for two 12"s and has a slot port in the middle. I have done TONS of reading and my confusion is still: when making calculations using the box dimensions do I include the width of the slot or completley ignore that part. Also, the slot is made with a particular length (10.5") of 0.75" MDF wood. Is there a formula for how much volume that would take up, i.e. the slots is made of two pieces of wood that are .75" thick, 12.5" tall and the length is 10.5".
i wish I could draw a picture, but like I said it has one slot in the middle.
PRIMARY QUESTION IS:
To measure the internal volume do I exclude the section that makes the slot port, i.e. subtract 0.75" X2 (thickness of both pieces of wood that make the slot port) and subtract the 2.5" that acutally makes the hole from the total width?
FYI, the dimensions are as follows...
outside dimesions of box...
H 14"
W 32"
D 15.5"
Square port (not including the thickness of the wood):
W 2.5
H 12.5
the length is 10.5"
I know the box is really small and probably tuned really high (and therefore will likely sound like crap), but it was cheap and I want to see how it sounds and would still like to be able to figure out the frequency it is at.
all stabs at answering this post are appreciated
Thank you
ps
FYI: I understand generally how to get volume, i.e. in the case of a sealed enclosure.
I know it won't "fix" the lack of size, but I am hoping that polyfill will help if needed once I figure out the numbers. Additionally, I have 2 JL12w6v2s that the manufacturer recommends only 1.5cf for each in a vented enclosure anyhow...
addendum:
will using polyfil increase the tuning (by decreasing volume) or will it actually decrease tuning by its "slowing down of the air effect"?