its_ray_ray 10+ year member
FTW Michael Jackson Mario
i have never actually used my dmm to set all settings on my amps. i have always been a "by the ear" kind of guy. well my old dmm took a **** on me. so i bought a new one yesterday. can anyone explain to me how to use this formula and what-not.
i'm going to be running the audiopipe ap-3002 i picked up. and i will be running it bridged @ 4 ohms.
Can anyone explain how to use the forumla so i can tune my amp? lol
AP-3002
Frequency Response
20Hz – 20kHz
Signal to noise ratio
110dB
Channel separation
>75dB
Total harmonic distortion
Speaker impedance
2 ohm to 4 ohm
Input sensitivity
0.25V – 8V
Crossover frequency
55Hz – 5.5Khz 12dB stereo
Bass boost
0 – 18dB @ 45Hz
Output power (RMS)
Stereo 2 CH – 160W x 2 @ 4 ohms
Stereo 2 CH – 320W x 2 @ 2 ohms
Bridged 1 CH – 640W x 1 @ 4 ohms
P = Power in watts
I = Current in amperes
R = Resistance in ohms (effectively the nominal impedance)
V = Potential in volts (Voltage)
Knowns:
Resistance (nominal impedance of your speakers)
Power (desired wattage)
Unknowns:
Voltage (we'll measure this)
Current
Formulas:
P = I*V (formula for power)
V = I*R (Ohm's law)
So after a little substitution to get Voltage in terms of simply power and resistance we get
V = square_root(P*R)
i'm going to be running the audiopipe ap-3002 i picked up. and i will be running it bridged @ 4 ohms.
Can anyone explain how to use the forumla so i can tune my amp? lol
AP-3002
Frequency Response
20Hz – 20kHz
Signal to noise ratio
110dB
Channel separation
>75dB
Total harmonic distortion
Speaker impedance
2 ohm to 4 ohm
Input sensitivity
0.25V – 8V
Crossover frequency
55Hz – 5.5Khz 12dB stereo
Bass boost
0 – 18dB @ 45Hz
Output power (RMS)
Stereo 2 CH – 160W x 2 @ 4 ohms
Stereo 2 CH – 320W x 2 @ 2 ohms
Bridged 1 CH – 640W x 1 @ 4 ohms
P = Power in watts
I = Current in amperes
R = Resistance in ohms (effectively the nominal impedance)
V = Potential in volts (Voltage)
Knowns:
Resistance (nominal impedance of your speakers)
Power (desired wattage)
Unknowns:
Voltage (we'll measure this)
Current
Formulas:
P = I*V (formula for power)
V = I*R (Ohm's law)
So after a little substitution to get Voltage in terms of simply power and resistance we get
V = square_root(P*R)