final ohm load of 2 different ohm speakers

[bobo244 10+ year member]

On my little pioneer deck reciever, i want to wire the original speakers that came with it, dont know the impedence, and some JBL bookshelf speakers, 8ohm, would the final load be (8 + X)/2?

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[CodySt]

I think it would be

(8 + Difference in the ohm loads)/2

So the 8ohm and a 4ohm would be like this (I think)

(8 + 4) / 2 = 6ohm load?

Dont quote me on that, but I believe that's how you do it using simple algebra skills.

 

[geolemon 10+ year member]

Yes, but the problem would be the resulting differential in power routed to the two different speakers...

With one 8 ohm speaker, and one 4 ohm speaker, the 4 ohm speaker would be getting 2/3 of the power produced from the amplifier, with the 8 ohm speaker receiving only 1/3 of the power.

...Not really a problem IF the 8 ohm speaker is a lot more efficient than the 4 ohm speaker - but you can see the potential problem. //content.invisioncic.com/y282845/emoticons/wink.gif.608e3ea05f1a9f98611af0861652f8fb.gif

 

[Fordfool302 10+ year member]

I'm a little confused about what your runin and how many your runin but if your gonna run speakers on a amp or a deck not bridged to seperate channels with different channel you will mess the deck or the amp up over time with different impedences on different channels.

 

[bobo244 10+ year member]

I'm a little confused about what your runin and how many your runin but if your gonna run speakers on a amp or a deck not bridged to seperate channels with different channel you will mess the deck or the amp up over time with different impedences on different channels.

im a little confused on what you just tried to say......

im thinking of taking my pioneer reciever, im guess its around 60 or so wrms X 2 and running 2 speakers, in parallel, off each channel. just trying to add 2 extra speakers each receiving close to what they would reciever if hooked up by themselves...

not really worried about the 1/3 power and 2/3 power thing......

 

[bobo244 10+ year member]

i just have 2 extra speakers not being used, might as well hook them up right?

 

[brynm 10+ year member]

If it's 8ohms and 4 ohms in parallel you would get 2.7ohm final in series it would be 12 ohm. unless your amping them on a 2ohm stable amp it won't work for sh!t and as mentioned above the 4 ohm set would be getting 2/3 of the power

 

[brynm 10+ year member]

this site has a good calc to figure out ohm loads

http://www.the12volt.com/caraudio/boxcalcs.asp