Can someone help me calculate internal volume?

agarabaghi
10+ year member

Senior VIP Member
Wood thickness 0.75

Width at all sections is 13"

All dimensions are outside dimensions

boxh.jpg


I need vol before displacement

The box is for a SA10, which im assuming is about 0.12 displacement?

 
I finall different recommendations for this sub:

Sundown Sa10

from sundownonly.com

Displacement 0.10 ft^3

Sealed box 0.5 cu. ft.

Ported box 0.75-1.0 cu. ft.

from ssa:

VENTED :

1.25 - 1.5 cubic feet tuned to 30 - 35 Hz

Yields F3 in the mid to high 20s

SEALED :

0.55 cubes for 0.707 Qtc alignment

Yields F3 of 50 Hz

 
why is this so hard lol...

im taking 2 boxes:

12.75 x 12 x 13

8.25 x 15 x 13

and putting each into 12v calc:

0.79

0.61

add them up

1.4

subtract .1 for displacement

1.3ft^3...?

 
Are u subtracting 3/4 inch .for wall of box on each side. 1.56 before displacement 1.4 after not that .1 of a cube is a big deal but I figured using cu in and converted to cu ft about as accurate as youll get.

 
pro-rabbit confirmed it was 1.39ft^3 before displacement, and going by the SA10 .10 displacement spec that would be 1.29ft^3...

Going to try a 3" x 15" aero port for a 30hz tuning will let you know how it sounds.

 
[(10.5*11.25*11.5)+(14.25*6.75*11.5)+(0.75*6.75*11.5)]/(12*12*12) = 1.46 ft^3 before displacement.

Far left rectangle, far right rectangle, airspace you subtracted from the wood thickness in between the two main rectangles that actually exists, divided all by 12^3 to change in^3 to ft^3.

 
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