Ohm equation help

[maylar 10+ year member]

(Power @ 2 ohm)(.5)+(power @ 2 ohm)/(3)
Ocorrect me if I'm wrong.

Let's try it this way...

3 X 4 ohm in parallel = 1.33 ohms which might be too low for the amp? (I dunno the specs). Or 3 X 1 ohm in series = 3 ohms (original posters idea?)

So, the amp will put out 2500 watts @ 2 oms, which is 70.7 volts. At 3 ohms that should be 1666 watts.

 

[KJThaDon 10+ year member]

You'll likely rise >2 ohm anyway. That's your best bet right there.

What do you mean by rise?

Let's try it this way...
3 X 4 ohm in parallel = 1.33 ohms which might be too low for the amp? (I dunno the specs). Or 3 X 1 ohm in series = 3 ohms (original posters idea?)

So, the amp will put out 2500 watts @ 2 oms, which is 70.7 volts. At 3 ohms that should be 1666 watts.

Thank you!