Papermaker85
5,000+ posts
Banned
OMG did I not just do the math?voltagexamperage is powerI'll definitely get some pictures up sometime. I'm actually headed home now to begin tilling up an area for a garden and get away from a computer screen for abit. //content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif
Amperage flowing across an impedance can be used to determine approximate power. //content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif The thing is all 3 (4 w/ phase angle) entities are interconnected *shrug* Assuming your load isn't 0 or infinity you will have both voltage and current.
but measure pricks with you later amigo. try not to die of boredom until I decide to bless you with my presence again //content.invisioncic.com/y282845/emoticons/suave.gif.858fc102f7646e678ee8af7e1fbc41d1.gif
if you know power and resistance the squareroot of power*resistance will give you voltage
if you know power and resistance and want to find amperage you find the square root of power/impedance.
I'm not sure what your not understanding money..
furthermore I wrote the post
20kw on a two ohm driver has the same amperage as 5kw on the 1/2 driver.
which one will be louder? which one will have more? its a legitimate question and applies to the original post..
