Is this right!?!?!

[1990RANGER 10+ year member]

I’m doing calculations to build a box for (2) 15” Kicker COMPVRs. This is what I have so far:

(Vb) Internal Dimensions: 11,355.80 in^3

(Fb) Tuning Frequency: 32 Hz

(Av) Port Area (face): 152 in.^2 (4 in. x 19 in.)

(Lv) Port Length: solving for

Then I plugged it into the equation in George’s ported box building thread:

-Lv = (Av)*1.84*10^8/[(Vb)*1728*((Fb)/0.159)^2] - 0.823*sqrt(Av)

-Lv = 152*1.84*10^8/[(11,355.80)*1728*(32)/0.159)^2] - 0.823*sqrt(152)

-Lv = -10.11 in.

Is this right, cause I don’t think Lv should be negative? Oh, and would I be better off calculating the port wall length for just one chamber and then apply the wall length to both? Cause I’m building 1 port per chamber, so there will be 2 separate ports in total when all is said and done.

Also, the (Av) Port Area measurement above is the combination of both of the separate ports I’m talking about.

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[Harrison486 10+ year member]

I tried learning from Georges post and it didn't work.

I had to learn other ways.

 

[1990RANGER 10+ year member]

//content.invisioncic.com/y282845/emoticons/frown.gif.a3531fa0534503350665a1e957861287.gif, oh well at least I didn't get too far in the calculations.

 

[cjjackson85 5,000+ posts]

Yeah.