1990RANGER 10+ year member
Where Am I???
I’m doing calculations to build a box for (2) 15” Kicker COMPVRs. This is what I have so far:
(Vb) Internal Dimensions: 11,355.80 in^3
(Fb) Tuning Frequency: 32 Hz
(Av) Port Area (face): 152 in.^2 (4 in. x 19 in.)
(Lv) Port Length: solving for
Then I plugged it into the equation in George’s ported box building thread:
-Lv = (Av)*1.84*10^8/[(Vb)*1728*((Fb)/0.159)^2] - 0.823*sqrt(Av)
-Lv = 152*1.84*10^8/[(11,355.80)*1728*(32)/0.159)^2] - 0.823*sqrt(152)
-Lv = -10.11 in.
Is this right, cause I don’t think Lv should be negative? Oh, and would I be better off calculating the port wall length for just one chamber and then apply the wall length to both? Cause I’m building 1 port per chamber, so there will be 2 separate ports in total when all is said and done.
Also, the (Av) Port Area measurement above is the combination of both of the separate ports I’m talking about.
(Vb) Internal Dimensions: 11,355.80 in^3
(Fb) Tuning Frequency: 32 Hz
(Av) Port Area (face): 152 in.^2 (4 in. x 19 in.)
(Lv) Port Length: solving for
Then I plugged it into the equation in George’s ported box building thread:
-Lv = (Av)*1.84*10^8/[(Vb)*1728*((Fb)/0.159)^2] - 0.823*sqrt(Av)
-Lv = 152*1.84*10^8/[(11,355.80)*1728*(32)/0.159)^2] - 0.823*sqrt(152)
-Lv = -10.11 in.
Is this right, cause I don’t think Lv should be negative? Oh, and would I be better off calculating the port wall length for just one chamber and then apply the wall length to both? Cause I’m building 1 port per chamber, so there will be 2 separate ports in total when all is said and done.
Also, the (Av) Port Area measurement above is the combination of both of the separate ports I’m talking about.
