Just to elaborate on what PV is saying, let's add some math...
Say you are sending subwoofer A 1500w RMS @ 1 ohm with a clean sine wave. We'll say the frequency is equal to that of a fundamental sine wave.
Voltage = SQRT(W*R) = sqrt(1500 * 1) = sqrt(1500) = 38.72v
This is RMS wattage. Divide this by .707 and you get 54.76v peak voltage.
So now we have the peak and the period of the sine wave, so lets make it into an equation we can integrate.
Y = 54.76 sin(x)
Integrate this equation from 0 to Pi, and you will get the area under the curve.
54.76*-cos(pi) - 54.76*-cos(o)
54.76 + 54.76 = 109.52 units^2
Now for the easy part. A full square wave from 0 to pi is simply multiplying the length times the height. In this case, the length is Pi and the height is 54.76 (volts)
Pi * 54.76 = 172.03
Divide 172 by 109; This will give you the percentage increase in RMS wattage.
172/109 = 157%
Multiply by the original RMS wattage.
1500* 1.57 = 2355w
Although this is the extreme case of a fully clipped signal (Which isn't too hard to achieve anyway), it shows you that you can go from 1500w to a whopping 2355 by clipping.
Edit: After doing all this work I forgot I could've pulled the 54.76 out of the equation and simply integrated sin(x) from 0 to Pi and then multiplied after !