Could someone calculate this space for me?

[95Prober 10+ year member]

Hi guys,

I was wondering if I could get some help calculating my internal volume. Its pretty straight foward, but I wanna make sure.

The EXTERNAL dimentions : 14.5" x 32" x 34" and will be a sealed box using 3/4" MDF (I didnt build it yet), for four 12" subs.

Now, I want divide the box internally into 4 different chambers with the 3/4" MDF.

So after I take into account, the dividers, I need to minus the sub displacement for each sub in each chamber, which is 0.12 cu.ft.

Would anyone be able to figure out my NET cu.ft. space that Ill have remaining for each sub?

Thanks for the help!!!

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[psych0ticnemes1 5,000+ posts]

Is there a reason why you want 4 chambers? It seems like more work than it is worth.

 

[fasfocus00 5,000+ posts]

since you don't know how to use a calculator to multiply and divide. you can do it yourself here:

http://www.rockfordfosgate.com/rftech/box_wizard.asp

 

[JusBlaze 10+ year member]

7.46 cu gross

 

[95Prober 10+ year member]

Is there a reason why you want 4 chambers? It seems like more work than it is worth.

well, the guys at Image Dynamics said its preferred that each IDMAX have its own chamber if possible

 

[Supergumby5000 5,000+ posts]

its much better in a sealed application to have each driver have its own chamber. you risk damaging ALL of your subs if one goes out when they are sharing a chamber

 

[Supergumby5000 5,000+ posts]

and if you did that box with four separate chambers, with a single 0.75" sheet breaking apart each chamber, you are looking at 1.77 cubic feet per...

 

[95Prober 10+ year member]

and if you did that box with four separate chambers, with a single 0.75" sheet breaking apart each chamber, you are looking at 1.77 cubic feet per...

So, is that 1.77 cu.ft the net cu.ft after taking into account the .75" dividers inside?

yes, ill be using single 0.75" dividers. basically a " + " shpae inside the box.

also, is the 1.77 cu.ft AFTER minusing sub displacement?

thx

 

[Supergumby5000 5,000+ posts]

So, is that 1.77 cu.ft the net cu.ft after taking into account the .75" dividers inside?yes, ill be using single 0.75" dividers. basically a " + " shpae inside the box.

also, is the 1.77 cu.ft AFTER minusing sub displacement?

thx

the four chambers will be 1.77 cubic feet before any displacements added into them. So, subtract whatever your displacement is due to polyfill/subs/whatever from that number, and thats your volume for each chamber.