poundin s-10 10+ year member
Member
just as the title says, i want to know if my calculations are correct.
i am building a box for 3 12" jl audio w'6s.
the jl site reccomends the box that is 17" x 12" x 16.5". the port would be 1.25" x 10.5" x 25.5" making the face of the port 13.125: squared.
any ways if im not mistaken, A= PI x RADIUS squared . i know the area is 13.125" so this makes the equation 13.125= 3.14 x (X)squared... so if i take 13.125 and devide it by PI (3.14) that would give me 4.18. then if i find the square root of 4.18 that would give me appox 2.045 inches for the radius, making the diameter of the pipe 4.18"... in short, what i want to know is if 3 pieces of pipe 4" in diameter and 25" long will work for a box for 3 jl w6's, thanks
i am building a box for 3 12" jl audio w'6s.
the jl site reccomends the box that is 17" x 12" x 16.5". the port would be 1.25" x 10.5" x 25.5" making the face of the port 13.125: squared.
any ways if im not mistaken, A= PI x RADIUS squared . i know the area is 13.125" so this makes the equation 13.125= 3.14 x (X)squared... so if i take 13.125 and devide it by PI (3.14) that would give me 4.18. then if i find the square root of 4.18 that would give me appox 2.045 inches for the radius, making the diameter of the pipe 4.18"... in short, what i want to know is if 3 pieces of pipe 4" in diameter and 25" long will work for a box for 3 jl w6's, thanks