Anyone know how to....

[adulbrich 5,000+ posts]

Do this?

Or this??

Or this???

Wat is the intermediate value theorem //content.invisioncic.com/y282845/emoticons/confused.gif.e820e0216602db4765798ac39d28caa9.gif

Last six math questions I have for homework.

Click to read more...

 

[speedyjuarez Premium Member]

The answer is 2

 

[honkyg 10+ year member]

**** no,.. i grew up in an age where they didnt bombard you with mathmatics you'll rarely use. lol

 

[adulbrich 5,000+ posts]

//content.invisioncic.com/y282845/emoticons/frown.gif.a3531fa0534503350665a1e957861287.gif

Calculus........

 

[Slo_Ride 5,000+ posts]

Calculus. I see in calculus. Calculus. Calculus.

 

[hispls 5,000+ posts]

Perhaps if you had been paying attention in class you'd know the answer.

 

[Boomin_tahoe 5,000+ posts]

yearssssssssss ago calculus was taught in college.

Now they're pushing for middle schoolers to do that *****.

 

[adulbrich 5,000+ posts]

Perhaps if you had been paying attention in class you'd know the answer.

I was too busy arguing with someone on this forum while I was supposed to be taking notes //content.invisioncic.com/y282845/emoticons/crap.gif.7f4dd41e3e9b23fbd170a1ee6f65cecc.gif

Now I'm hoping this forum can get me out of this predicament

 

[bubbagumper6 5,000+ posts]

I was too busy arguing with someone on this forum while I was supposed to be taking notes //content.invisioncic.com/y282845/emoticons/crap.gif.7f4dd41e3e9b23fbd170a1ee6f65cecc.gif
Now I'm hoping this forum can get me out of this predicament

Maybe you should...oh I don't know...read your textbook? Generally all the concepts taught in class are in the textbook >_>

 

[adulbrich 5,000+ posts]

Maybe you should...oh I don't know...read your textbook? Generally all the concepts taught in class are in the textbook >_>

We don't have textbooks because the class sizes are so large now, and not everyone would be able to get a book. The school can't afford to buy more, because our state funding got severely cut

 

[bubbagumper6 5,000+ posts]

We don't have textbooks because the class sizes are so large now, and not everyone would be able to get a book. The school can't afford to buy more, because our state funding got severely cut

Wow, that's some bullshit, how are you supposed to learn without a textbook.....I guess start googling bro. The collective knowledge of the internet is better than any textbook anyway. I would try to help but it's been a long time since I've had to do any calculus and even though I'm an engineer by trade it's still something I haven't used since school, haha.

 

[bubbagumper6 5,000+ posts]

Actually after googling the intermediate value theorem, this is really not that difficult. All you have to do is solve the equation with each of the two bounds to show one is positive and one is negative (i.e. the line crosses the zero line). Then use your graphing calculator to estimate what the value of x is at that point. The second one is the same concept except they give you a value and you have to solve backwards for x...The last one is the same as the second except your solving for f©=0

 

[agcelica]

Woo! Calc major right here.

So the intermediate value theorem tells you that if an equation = 6 at one point and = 7 at the next point (those are y values), then between those 2 point the equation must pass through every value between 6 and 7. Basically it cant just jump from 6 to 7 without passing say 6.5 or 6.7 but that it must hit every value between them at once.

So for number 23 for example it wants to know how you know that equation = 0 between 1 and 2 on the x axis. So if 0 is in the middle then it must go from positve to negative or negative to positive right? so at x=1 that equation = 1/12 - 1 + 4 = 2.917

at x = 2 the equation = -2.67

So for that equation to go from 2.917 to -2.67 on the y axis it must pass through 0. therefore you know that there must be a 0 between 1 and 2 on the x axis at least once

Kind of make sense?

 

[agcelica]

Woops double post.

you will have to do the calculator part yourself. I dont have on handy

 

[adulbrich 5,000+ posts]

Wow, that's some bullshit, how are you supposed to learn without a textbook.....I guess start googling bro. The collective knowledge of the internet is better than any textbook anyway. I would try to help but it's been a long time since I've had to do any calculus and even though I'm an engineer by trade it's still something I haven't used since school, haha.

Yeah

Actually after googling the intermediate value theorem, this is really not that difficult. All you have to do is solve the equation with each of the two bounds to show one is positive and one is negative (i.e. the line crosses the zero line). Then use your graphing calculator to estimate what the value of x is at that point. The second one is the same concept except they give you a value and you have to solve backwards for x...The last one is the same as the second except your solving for f©=0

I guess I'll have to do some more googling, cuz this still isn't making sense

Woo! Calc major right here.So the intermediate value theorem tells you that if an equation = 6 at one point and = 7 at the next point (those are y values), then between those 2 point the equation must pass through every value between 6 and 7. Basically it cant just jump from 6 to 7 without passing say 6.5 or 6.7 but that it must hit every value between them at once.

So for number 23 for example it wants to know how you know that equation = 0 between 1 and 2 on the x axis. So if 0 is in the middle then it must go from positve to negative or negative to positive right? so at x=1 that equation = 1/12 - 1 + 4 = 2.917

at x = 2 the equation = -2.67

So for that equation to go from 2.917 to -2.67 on the y axis it must pass through 0. therefore you know that there must be a 0 between 1 and 2 on the x axis at least once

Kind of make sense?

Still kinda fuzzy