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<blockquote data-quote="agcelica" data-source="post: 8440561" data-attributes="member: 664119">Woo! Calc major right here.So the intermediate value theorem tells you that if an equation = 6 at one point and = 7 at the next point (those are y values), then between those 2 point the equation must pass through every value between 6 and 7. Basically it cant just jump from 6 to 7 without passing say 6.5 or 6.7 but that it must hit every value between them at once.So for number 23 for example it wants to know how you know that equation = 0 between 1 and 2 on the x axis. So if 0 is in the middle then it must go from positve to negative or negative to positive right? so at x=1 that equation = 1/12 - 1 + 4 = 2.917at x = 2 the equation = -2.67So for that equation to go from 2.917 to -2.67 on the y axis it must pass through 0. therefore you know that there must be a 0 between 1 and 2 on the x axis at least onceKind of make sense?</blockquote>

[QUOTE="agcelica, post: 8440561, member: 664119"] Woo! Calc major right here. So the intermediate value theorem tells you that if an equation = 6 at one point and = 7 at the next point (those are y values), then between those 2 point the equation must pass through every value between 6 and 7. Basically it cant just jump from 6 to 7 without passing say 6.5 or 6.7 but that it must hit every value between them at once. So for number 23 for example it wants to know how you know that equation = 0 between 1 and 2 on the x axis. So if 0 is in the middle then it must go from positve to negative or negative to positive right? so at x=1 that equation = 1/12 - 1 + 4 = 2.917 at x = 2 the equation = -2.67 So for that equation to go from 2.917 to -2.67 on the y axis it must pass through 0. therefore you know that there must be a 0 between 1 and 2 on the x axis at least once Kind of make sense? [/QUOTE]

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