Algebra II problem

[4runnercrazy 10+ year member]

well i took the class last yr and a friend wants help and i for get how to do it

n e one want to take a stab, becasue i know car audio ppl are suppost to be good at math

find all real values of k for which 3t^2-4t+k=0 has imaginary roots

Click to read more...

 

[Mitch86 5,000+ posts]

You like George Bush... you cant be helped.

 

[937DYTBOI 5,000+ posts]

the answers are so easy

 

[LinxuS 10+ year member]

any time k > 16/12.

x = (-b) +/- (sq rt (b^2 - 4 a c))

---------------------------

2 a

So its not a real number when you take the sq root of a negative (a.k.a. imaginary roots.)

3x^2 - 4x + k = 0

a = 3

b = -4

c = k

so basically

when

B^2 - 4ac is negative

(-4)^2 - 4(3)(k)

16 - 4(3)(k)

16 - 12(k)

-12k

k > 16/12

so 12 x 16/12 or anything greater would give you a negative number.

Does that make sense?

 

[jmanpc 5,000+ posts]

the square root of my nuts is skeet.

 

[4runnercrazy 10+ year member]

You like George Bush... you cant be helped.

sry n e non hippi's want to help

if u had a prolem and u liked kerry i would still help ya

 

[4runnercrazy 10+ year member]

any time k > 16/12.
x = (-b) +/- (sq rt (b^2 - 4 a c))

---------------------------

2 a

So its not a real number when the sq root is negative

3x^2 - 4x + k = 0

a = 3

b = -4

c = k

so basically

when

B^2 - 4ac is negative

(-4)^2 - 4(3)(k)

16 - 4(3)(k)

16 - 12(k)

-12k

k > 16/12

so 12 x 16/12 or anything greater would give you a negative number.

Does that make sense?

it does thank bud

 

[LinxuS 10+ year member]

Sure np. I love math, so its always good to help someone out.

 

[4runnercrazy 10+ year member]

Sure np. I love math, so its always good to help someone out.

yea i love math 2 except some how i dont remember everyhting from last yr

 

[LinxuS 10+ year member]

Yeah i had no idea how to do that until I thought about it for a second.

AP Calculus and Physics FTL haha. Made me forget a lot about algebra.

 

[4runnercrazy 10+ year member]

Yeah i had no idea how to do that until I thought about it for a second.AP Calculus and Physics FTL haha. Made me forget a lot about algebra.

yea im in AP stats now and it sucks

 

[ndnbolla 10+ year member]

Now can you help me find the total gravitational force and horizontal force for a point moving along the parabola 8y=4x^2-16 from point (0,-2) to (2,0) where the horizontal force is equal to the y value pointing in the positive x direction.

So total force equals...? (Hint, use integrals //content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif )