4 12's or.... 2 12's & 2 10's

[cotjones 10+ year member]

Yes, the 13" driver has a higher POTENTIAL linear displacement, I don't think you realize that either setup will almost never use their full linear excursion.

it doesn't matter if they don't use their full linear excursion because that is only the maximum out put

Say you give both setups a certain amount of power, that allows them both to reach 10mm of xmax, the 10" setup has more piston area that the 1 13" and since they're both at the same level of excursion at this point surface area is going to dictate which setup will have more output, and since the 10" drivers do they will be louder.

yes if they are both at 10mm of excursion than the 10's will be louder, but to reach 10 mm the 10's will have to use far more power to do it so that means the 13 is louder (see below)

The 10" setup will be louder up to a point, I don't understand why you can't see that, basing your entire argument on x is louder than y because it has a higher linear displacement, is trivial at best, you're not seeing that you almost NEVER use a driver's full linear displacement.

it's not trivial your aren't listening... you are basically saying that all 10's are the same and their excursion capability doesn't effect their whole performance only the max

Since you said X, and I know my math is a little rusty, but generally when X is used as a variable, it's the same in the entire equation, so uhhh if X=500 then 2x=1000, and since we're talking about 1 driver compared to 2, the 2x would be the 10s.

exept you don't double the x when going into the 10's... think of it this way you have 2 different functions y=(x)into 2 10's

Z=(x)into 1 13

now x is one value of power ... if that value of power is the same in both equasions the 13 will ALLWAYS be louder using the same amount of power

ok so lets say you give the 13 250 and only 200 to each of the tens... but you forget it takes 2 of them to get to the output of the 13, so it's really 400 watts...

You're also assuming that the 13" driver will be more efficient, even with what you listed up there, you don't know anything for certain so you can't say x will be louder than y, because you just don't know.

i know that at xmax, the 13 moves 277% more air than the 10's which is the ONLY thing i need to know to say "1 13 is louder than 2 10's"
oh and i don't really give a fvck about the other threads, yeah i said some dumb stuff, yes i have learned alot, now i'm appearantly more knowledgeable than alot of you and the only arguement you have left to hold on to is some of the dumb stuff i've said in the past. get a life because you can't correctly tell me i'm wrong you just attack me

 

[cotjones 10+ year member]

not tryin to be a d ick jus wondering why you wouldnt do that.

//content.invisioncic.com/y282845/emoticons/read.gif.ff512c499c00ed3faae9a20f4b088b29.gif

 

[cotjones 10+ year member]

cotjones send me 2 of your 10s and your 13" sub. Ive got a smaller amp that should do fine. Ive got feedback and will pay for shipping. I will build two boxes both tuned to 34hz and meter them. Lets see which is louder.

well thats wrong because they shouldn't both be tuned to 34 they are diff. subs, but yes the 13 will be louder honesly have you ever compared them?

and like i would ever just send you my subs

 

[cotjones 10+ year member]

Ive got references and wouldnt scam you but eh Ill tune em to whatever JL suggests.

ummm no as dumb as some of the comments you gave me are... under no circumstances would i EVER send you anything i don't want to blow up... but you'd do that and you don't think the 13 would beat the 10's?

 

[PendulousThread 10+ year member]

so why dont u sell ur 10's and buy 13's ??? i read the thread thank you.

 

[cotjones 10+ year member]

not tryin to be a d ick jus wondering why you wouldnt do that.

cause i can't gett them for that price anymore.. it would be a pain in the *** to get a good amount of money out of them, plus i'm happy with it now, so when i get the new car i'll buy something new and just keep the old setup

 

[PendulousThread 10+ year member]

o.

 

[cotjones 10+ year member]

As dumb as I am? Im about to ****ing buy some JL 10s right now and ****ing own your *** with them. I have no doubt anything you do will never touch any of my set-ups. Yes I will blow them god your a ****ing tool. Go ********** to your JL icons and get out of your own ****ing dream world kid. I guarantee 2 10s would ****ing *** **** the 13 granted they are both properly designed and tuned boxes. Shit I am half tempted to find someone in Charlotte and get you metered and beat your score with 2 10s. No doubt its possible.

see as "scarey" as that thread sounds every bit of it is ur opinion and attitude as the king of box building... please explain to me how subs that have less potential to move air have the potential to be louder, if you can

 

[cotjones 10+ year member]

your arguement makes littereally NO sence... a 13w6 litterally functions as if it were 2.77 10w6's useing less power!!! the sole reason i'm being disagreed with right now is because of that other thread that was quoted earlier, and thats just retarded and immature. there are a bunch of people who are going to go out and spen alot more money to get something not as good thanks to you guys!

 

[cotjones 10+ year member]

so why dont u sell ur 10's and buy 13's ??? i read the thread thank you.

sry i thought you said why would i do that (talking about getting the 13) my bad

 

[bass_lover1 10+ year member]

it doesn't matter if they don't use their full linear excursion because that is only the maximum out put

Uhh, isn't that what your argument was that the 13 will be louder because it has higher linear displacement, now you're back stepping.

yes if they are both at 10mm of excursion than the 10's will be louder, but to reach 10 mm the 10's will have to use far more power to do it so that means the 13 is louder (see below)

How do you know that? You're assuming that they will require more power, you haven't proven it yet, and I doubt you will.

it's not trivial your aren't listening... you are basically saying that all 10's are the same and their excursion capability doesn't effect their whole performance only the max

lmao, I never said that, you're reading comprehension isn't up to par. If you take two random 10" drivers, both with the same Sd, if you give each the power required to move them to 10mm of xmax, then YES they will have the same output, while one may run out of usable linear excursion early, only at that point will the other have more linear displacement because it has more linear excursion, but up until that point they will have the same output.

exept you don't double the x when going into the 10's... think of it this way you have 2 different functions y=(x)into 2 10's

Z=(x)into 1 13

now x is one value of power ... if that value of power is the same in both equasions the 13 will ALLWAYS be louder using the same amount of power

How do you know that? You don't, you don't know that with a given power that driver X will high a higher excursion, you're making blind statements that you have no way to back up.

ok so lets say you give the 13 250 and only 200 to each of the tens... but you forget it takes 2 of them to get to the output of the 13, so it's really 400 watts...

Ok, and what is that proving? Besides the fact that you just backed up my statements, that the 10s can have more output than the 1 13, thanks //content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif

i know that at xmax, the 13 moves 277% more air than the 10's which is the ONLY thing i need to know to say 1 13 is louder than 2 10's"

if you followed that up with "at xmax" then yes I would agree with you, otherwise you're wrong. Yes the 13 may have a higher potential linear displacement, but it will not always be louder.

oh and i don't really give a fvck about the other threads, yeah i said some dumb stuff, yes i have learned alot, now i'm appearantly more knowledgeable than alot of you and the only arguement you have left to hold on to is some of the dumb stuff i've said in the past. get a life because you can't correctly tell me i'm wrong you just attack me

I wasn't around when that happened but I do know you made a bad name for your self, maybe you've changed, but so far you're making a lot of blind statements.

 

[ThomasG 5,000+ posts]

I f*cking love this thread...

Cotjones: somone prove me wrong

OT: proves him wrong

Cotjones: some bullshit... now ya see cmon someone prove me wrong

no matter what you tell this guy he wont admit it.. But theres no reason to complain because its entertaining as f*ck

 

[cotjones 10+ year member]

Uhh, isn't that what your argument was that the 13 will be louder because it has higher linear displacement, now you're back stepping.


How do you know that? You're assuming that they will require more power, you haven't proven it yet, and I doubt you will.

lmao, I never said that, you're reading comprehension isn't up to par. If you take two random 10" drivers, both with the same Sd, if you give each the power required to move them to 10mm of xmax, then YES they will have the same output, while one may run out of usable linear excursion early, only at that point will the other have more linear displacement because it has more linear excursion, but up until that point they will have the same output.

How do you know that? You don't, you don't know that with a given power that driver X will high a higher excursion, you're making blind statements that you have no way to back up.

Ok, and what is that proving? Besides the fact that you just backed up my statements, that the 10s can have more output than the 1 13, thanks //content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif

if you followed that up with "at xmax" then yes I would agree with you, otherwise you're wrong. Yes the 13 may have a higher potential linear displacement, but it will not always be louder.

I wasn't around when that happened but I do know you made a bad name for your self, maybe you've changed, but so far you're making a lot of blind statements.

ok i'm gunna try this again... if you take 2 different 10's... 1 of them reaches an xmax of 1 inch at 1000 watts the other hits 2 inches at 500 watts... the second one will be louder at every level of power... so the point?

yes when the 13 is at half potential, the 10's have the ability to beat it's output but to do so, the 10's have to be using quite a bit more than half their potential, half of the 13's potential is 250watts,

half of the 2 10's potential is, 400 watts, so the 13 is allready winning in out put and using far less power

i'll do some comparisons to help you better understand...

lets say x is the MAXIMUM potential of the 13

y is the MAXIMUM potential of the 2 10's

so x > y ...even you agreed to this

now some more comparisons

so your given is x>y

that means...

x/z > y/z ...this simply means that when both setups are at a certain percentage of their max, the 13 will always be louder...

x(f) > y(f) ... again this means that if both setups are given any (f) amount of power each, the 13 will always be louder...

further more... the point is (starting at maximum out put going down) the first time the 10's have the ability to match the output of the 13 is when the 13 is at 71% of it's potential,

even worse, to do it the 10's have to use their full potential and 800 watts.. to match the 13 at 71% and 355 watts... its safe to say without gray lines that the 13 stomps the 10's!

edit lose number

 

[cotjones 10+ year member]

I f*cking love this thread...
Cotjones: somone prove me wrong

OT: proves him wrong

Cotjones: some bullshit... now ya see cmon someone prove me wrong

no matter what you tell this guy he wont admit it.. But theres no reason to complain because its entertaining as f*ck

hey no one has proven me wrong so **** off:*******: //content.invisioncic.com/y282845/emoticons/*******.gif.a649d21efc0d1fd4890a6428166586c1.gif :*******:

 

[cotjones 10+ year member]

do you still not understand basslover?