School Help

[sws10]

anyone down to help me figure out these 4 probs? its balancing equations for chemistry

well anyway here they are:

1. __Fe(OH)3 = __Fe2O3 + __H2O

2. __Na2CO3 + __Ca(OH)2 = __NaOH + __CaCO3

3.__K3PO4 + __MgCl2 = __Mg3(PO4)2 + __KCl

4. __CO + __O2 = __CO2

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[bizflawless 5,000+ posts]

that class sucked

 

[bizflawless 5,000+ posts]

damn i cant remember how to do these //content.invisioncic.com/y282845/emoticons/crap.gif.7f4dd41e3e9b23fbd170a1ee6f65cecc.gif

 

[sws10]

anyone else?

 

[bizflawless 5,000+ posts]

should be easy with a chart.....maybe?

 

[sws10]

ehh im lost clueless

 

[go_go_thrash 10+ year member]

anyone down to help me figure out these 4 probs? its balancing equations for chemistrywell anyway here they are:

1. __Fe(OH)3 = __Fe2O3 + __H2O

2. __Na2CO3 + __Ca(OH)2 = __NaOH + __CaCO3

3.__K3PO4 + __MgCl2 = __Mg3(PO4)2 + __KCl

4. __CO + __O2 = __CO2

4. is 2,1,2

at least im pretty sure //content.invisioncic.com/y282845/emoticons/wink.gif.608e3ea05f1a9f98611af0861652f8fb.gif

Gogo

 

[Heresy 10+ year member]

anyone down to help me figure out these 4 probs? its balancing equations for chemistrywell anyway here they are:

1. __Fe(OH)3 = __Fe2O3 + __H2O

2. __Na2CO3 + __Ca(OH)2 = __NaOH + __CaCO3

3.__K3PO4 + __MgCl2 = __Mg3(PO4)2 + __KCl

4. __CO + __O2 = __CO2

1. 2, 1, 3

2. 1, 1, 2, 1

3. 2, 3, 1, 6

4. 2, 1, 2

I just did it because I haven't done chemistry in years even though I took about 4 years of it. Worry about all the elements except oxygen and hydrogen, and then use them at the end. That is the easiest way to do it. You balance one element at a time. Usually, these is an even number of elements on each side when you are done (problem 3 didn't do this but the majority do).