//content.invisioncic.com/y282845/emoticons/laugh.gif.48439b2acf2cfca21620f01e7f77d1e4.gif. It doesn't really work that way. How do you know what exact rms rating you're sending? are you playing sine wave all day long?Can somebody call me a dumbass?! Please!
I failed to realize that when running a ported enclosure the RMS for the CVR is only 300, not 400! I already blew out the CVR I bought. A little bit of fast talk got me a brand new one for free! So now I just need to see if that bastard has a sealed box, I got rid of my old one! //content.invisioncic.com/y282845/emoticons/frown.gif.a3531fa0534503350665a1e957861287.gif Maybe' I'll break out the table saw and router and make a new one!
Dude you are truely clueless.Can somebody call me a dumbass?! Please!
I failed to realize that when running a ported enclosure the RMS for the CVR is only 300, not 400! I already blew out the CVR I bought. A little bit of fast talk got me a brand new one for free! So now I just need to see if that bastard has a sealed box, I got rid of my old one! //content.invisioncic.com/y282845/emoticons/frown.gif.a3531fa0534503350665a1e957861287.gif Maybe' I'll break out the table saw and router and make a new one!
I've been trying to get the equation forever, but no one seems to know. I figured if I do the math without the impedance then it would be lower then what it should be. Am I correct in thinking this way? I'm running it at 2ohms, if that helps.You have no idea what power you were running if you forgot to factor in the speaker impedance.
watts = amps x volts is the equation I assume you are referring to. But, this is a general equation that assumes you know two of the three. Unfortunately however, if you didnt factor in the impedance the amp is running at, you cant know amps. Most amplifiers' output is directly related to the impedance it sees. If it puts out 500 watts at 4ohms, it will put out (approx) 1000 watts at 2ohms. For example, not referencing your amplifier.I've been trying to get the equation forever, but no one seems to know. I figured if I do the math without the impedance then it would be lower then what it should be. Am I correct in thinking this way? I'm running it at 2ohms, if that helps.
so Ive i measured the amps with the DDM, then I just multiply that by the voltage, in this case 12.6 and get my watts? I don't have to worry about the impedance if i do it this way? That's the way I did it, but I still thought you had to throw impedance in there somewhere.watts = amps x volts is the equation I assume you are referring to. But, this is a general equation that assumes you know two of the three. Unfortunately however, if you didnt factor in the impedance the amp is running at, you cant know amps. Most amplifiers' output is directly related to the impedance it sees. If it puts out 500 watts at 4ohms, it will put out (approx) 1000 watts at 2ohms. For example, not referencing your amplifier.
One last but.... but if you measured input amperage at the amplifier using a DMM, you already know that without having to worry about speaker impedance.
Watts = amps X volts.so Ive i measured the amps with the DDM, then I just multiply that by the voltage, in this case 12.6 and get my watts? I don't have to worry about the impedance if i do it this way? That's the way I did it, but I still thought you had to throw impedance in there somewhere.