Need a single sealed box design/plan/cutsheet

[xDATx 10+ year member]

For Rockford Fosgate Punch HX2 RFD2212

I have attached the PDF manual for the specs

If anyone can help I would greatly appreciate it.

thanks

Dan

Click to read more...

 

[dr_peeb 10+ year member]

For Rockford Fosgate Punch HX2 RFD2212
I have attached the PDF manual for the specs

If anyone can help I would greatly appreciate it.

thanks

Dan

For a sealed box just determine the max space you have to fit the box, and adjust from there using this formula:

L x W x H (all in inches) = cubic inches. Divide that by 1,728 to convert it to cubic feet.

Adjust the dimensions until you get the volume you want/ need.

 

[xDATx 10+ year member]

So if i want to get 1.50 Cu Ft what would be an example in dimensions?

 

[ciaonzo 5,000+ posts]

So if i want to get 1.50 Cu Ft what would be an example in dimensions?

C'mon, man. Give it a try, he just gave you all the numbers you need to start plugging away with a calculator.

 

[xDATx 10+ year member]

ok so 14" x 14" x 14" = 2744 divided by 1728 = 1.58 Cu Ft ?

 

[ciaonzo 5,000+ posts]

ok so 14" x 14" x 14" = 2744 divided by 1728 = 1.58 Cu Ft ?

You got it. //content.invisioncic.com/y282845/emoticons/wink.gif.608e3ea05f1a9f98611af0861652f8fb.gif

Don't forget to take into account the displacement of the other items in the enclosure that detract from the gross volume.

 

[xDATx 10+ year member]

huh? lol so if i use 3/4 MDF i have to count for that? now i'm confused.

 

[ciaonzo 5,000+ posts]

huh? lol so if i use 3/4 MDF i have to count for that? now i'm confused.

Things like drivers and braces will subtract from your initial volume leaving you with a net volume that may be less than your target volume. You should be using inside dimensions for figuring volume so you don't need to account for the material thickness unless it's an internal brace.

 

[xDATx 10+ year member]

ok so if my speaker dis. cu ft. is 0.069 I subtract that from 1.58 Cu Ft leaving me with 1.51 Cu ft?

 

[ciaonzo 5,000+ posts]

ok so if my speaker dis. cu ft. is 0.069 I subtract that from 1.58 Cu Ft leaving me with 1.51 Cu ft?

Yep. //content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif

 

[xDATx 10+ year member]

thanks for walking me through this I was a bit rusty...lol

 

[ciaonzo 5,000+ posts]

thanks for walking me through this I was a bit rusty...lol

No problem. There's lots more involved but at least now you know how to arrive at a required volume.

 

[DNick454 10+ year member]

Don't forget, if your BOX's dimensions are 14" X 14" X 14", then the INTERNAL dimensions are actually 12.5x12.5x12.5 because of the 1.5" you have to subtract the width of the two pieces of MDF from each dimension.

 

[ciaonzo 5,000+ posts]

Don't forget, if your BOX's dimensions are 14" X 14" X 14", then the INTERNAL dimensions are actually 12.5x12.5x12.5 because of the 1.5" you have to subtract the width of the two pieces of MDF from each dimension.

Things like drivers and braces will subtract from your initial volume leaving you with a net volume that may be less than your target volume. You should be using inside dimensions for figuring volume so you don't need to account for the material thickness unless it's an internal brace.

//content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif

 

[dr_peeb 10+ year member]

To be clear ... A 14" x 14" x 14" box made from 3/4" think MDF measures only 12.5" x 12.5" x 12.5" on the inside. So, while the outside volume of the box is 2,744 cu in (1.58 cu ft), the inside volume is only 1,953 cu in (1.13 cu ft)

From that #, then subtract out all other solid object(s) that will be in the box, including the sub itself, and any internal braces. The same MDF makes for good internal bracing. The # you're left with is your net volume. You need to adjust the box's overall dimensions until you get the correct net volume you need.