JimJ
5,000+ posts
Tangled Up in Blue
Alright...after being on campus for 12 hours, I'm starting to lose my sanity...I know the basic principle behind what I'm doing, I just can't get the numbers to work out well.
I'm trying to show that Q = 9,000 + 450e^-0.022t is the solution to the differential equation Q' = 198 - 0.022Q, with an initial value of Q(0) being 9,450. This is the decrease of a population of fish or something.
I know that you have to get the diff. equation into the form Q = Ce^kT, where k = the rate of decrease, -0.022 and the T is the time in months. Plug the initial value in for the population, set the time to zero and solve for C. That's alright.
Where I'm lost is where the 198 goes...I'm teh **** at algebra, so I'm probably forgetting where to put it...can someone work this out?
Math > me.
I'm trying to show that Q = 9,000 + 450e^-0.022t is the solution to the differential equation Q' = 198 - 0.022Q, with an initial value of Q(0) being 9,450. This is the decrease of a population of fish or something.
I know that you have to get the diff. equation into the form Q = Ce^kT, where k = the rate of decrease, -0.022 and the T is the time in months. Plug the initial value in for the population, set the time to zero and solve for C. That's alright.
Where I'm lost is where the 198 goes...I'm teh **** at algebra, so I'm probably forgetting where to put it...can someone work this out?
Math > me.
