help me understand...

[redlinese-r 10+ year member]

ok, this has always confused me, i do not understand it when, for example an amplifier specs are 175x2 @ 4ohms, 350x2 @ 2 ohms, and 700x1 @ 4 ohms. now, i do not understand the part of 350x2 @ 2 ohms. would that mean that the amplifier is using its bridge output in parallel to two 4 ohm subwoofer? what if it were 700x1 @ 2 ohms? would that be using a single DVC 4 ohm subwoofer with both voice coils wired in parallel? also, can someone explain the mono/stereo function, what does it mean when it says 700x1 @ 4 ohms mono or stereo? thanks and please forgive the ignorance.

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[qtipextra 5,000+ posts]

Well, one thing for sure, is mono= 1 channel (x1), stereo 2 channel (x2)

 

[Prowler573 5,000+ posts]

175w/channel X 2 channels @ 4 Ohm stereo means that the amp will produce 175 per channel across two channels when presented with a 4 Ohm load.

When you lower the resistance being shown to the amplifier to 2 Ohms rather than 4 Ohms when configured in stereo (2ch in this case) it will increase its output to 350w per channel across two channels.

When you bridge the amplifier to a single, mono channel (connect the positive output from one channel to whatever you're driving with it and the negative output from the other channel and select the mono mode if applicable to that specific amp) then the power output will increase to 700w but only on a single output.

What resistance load you will/can show the amplifier will be entirely dependent on the voice coil configuration of the sub(s) you choose to use.

Here's an incredibly handy page that gives the lowdown on possible final resistance loads for single and multiple subwoofers with both single and dual voice coils. It's only applicable to standard 2, 4, and 8 ohm voice coil subs so it really won't help with the subs that use 3 ohm, 6 ohm, or other non-standard coils but it's a start. //content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif

Hope this helps.

 

[fb4076 10+ year member]

so if option two (on the link you gave) is used, then one would have to look for an amp that makes the recommended power at 4 ohms? This is for the page for... Dual Voice Coil - 2 ohms x 2

 

[Prowler573 5,000+ posts]

Are we talking 2ohm X 2 coils on a single sub or two subs?

If a single sub then you'd be able to run either a 4 Ohm or a 1 Ohm final load and then find an appropriate amp for that usage.

If for two subs then you can run a .5 Ohm, 2 Ohm, or 8 Ohm final load and then again, find an amplifier suitable to that application.

 

[cjjackson85 5,000+ posts]

The rule of thumb is 1 capacitor per amp.

 

[fb4076 10+ year member]

Alright, it is for a single sub, that is what I really needed to know... thanks!

 

[redlinese-r 10+ year member]

ok then if it were 700x1 @ 2 ohms. that mean that the output through ONE channel, in this case, bridged, would be 700 watts to a 2 ohm sub OR wired parallel to only a SINGLE 4ohm each DVC subwoofer with both coils driven which would present the amplifier with a 2 ohm load, correct? thanks for all the info.

 

[squeak9798 5,000+ posts]

I have no idea what you just said.

If it were a 2-channel amp with a power rating of 700w x 1 @ 2ohm, then the amp would produce 700w when bridged into a 2ohm load, regardless of what that 2ohm load consisted of. That 2ohm load could be a 2ohm SVC sub, or a DVC 4ohm/coil sub with coils wired in parallel, or a DVC 1ohm/coil sub with coils wired in series, or two 4ohm SVC subwoofers wired in parallel, or four 8ohm SVC subwoofers wired in parallel, etc etc.

 

[Prowler573 5,000+ posts]

x2 on what Squeak said.

As I posted above the final resistance load that you present to the amplifier will be entirely dependent on the voice coil configuration of the sub(s) you choose to use and the manner in which you wire them.

You do not have to use any certain combination of subs to achieve a specific final impendence. There are too many different makes of subwoofer with too many variants of VC configuration to say you need to do it one specific way.

 

[fearthepand 10+ year member]

alright how can you run the wires in parrell like the one in the link (the one for 2subs/single voice coil- 4ohms) and get the 2 ohm load?

 

[Prowler573 5,000+ posts]

For two subwoofers that are both 4 Ohm SVC drivers for a final load of 2 Ohms:

You will connect the positive output on the amplifier and connect it to both positive inputs on the subwoofers. You will connect the negative output on the amplifier to both negative inputs on the subwoofers.

Nominal impendence shown to the amplifier should be 2 Ohms.

 

[redlinese-r 10+ year member]

I have no idea what you just said.
If it were a 2-channel amp with a power rating of 700w x 1 @ 2ohm, then the amp would produce 700w when bridged into a 2ohm load, regardless of what that 2ohm load consisted of. That 2ohm load could be a 2ohm SVC sub, or a DVC 4ohm/coil sub with coils wired in parallel, or a DVC 1ohm/coil sub with coils wired in series, or two 4ohm SVC subwoofers wired in parallel, or four 8ohm SVC subwoofers wired in parallel, etc etc.

thats basically what i meant, in just one long sentence. thanks.