getting three 10" id oem's

[etznova 10+ year member]

getting three of those image dynamics overstocks for my buddys 87 mustang what do you guys think dual 4 or dual 2 which should i get

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[bimma85 5,000+ posts]

what amp do ya have?

 

[etznova 10+ year member]

well right now he has a kenwood exclon 1000 or whatever they call it its a few years old

but i dont think it a monoblock

 

[bimma85 5,000+ posts]

specs?

 

[etznova 10+ year member]

well right off hand i dont remember let me see if i can find one real quik

 

[etznova 10+ year member]

i believe it is this one

http://cgi.ebay.com/KENWOOD-KAC-X520-1000W-EXCELON-POWER-AMPLIFIER_W0QQitemZ9704602936QQcategoryZ39734QQrdZ1QQcmdZViewItem

keep in mind that i might be able to use a memphis 1000d that i have sitting just dont know if it works so a different amp is a possiblity just which voice coil would offer more options

 

[James Bang 5,000+ posts]

if i had a monoblock 1 ohm stable amp, i would get two dual 2 and one dual 4. that's if im doing the math correctly.

 

[~Magick_Man~ 10+ year member]

you shouldnt mix up different ohm load subs, they will recieve different amounts of power

if you had 2 d2 wired to 2ohm and a single d4 wired to 2 ohm then the d4 would get the same power as the pair of the d2's

i believe that is how it works but i have been wrong before.

~Magick_Man~

 

[helotaxi 5,000+ posts]

As said above, it depends on the amp. The D4 will wire out to a 2.67 ohm load and the D2 will wire out to a 1.33 ohm load.

 

[etznova 10+ year member]

so i guess either way my buddy needs a new amp cause i don't think that kenwood i stable bridged below 4ohm

 

[Rsx_03 10+ year member]

you shouldnt mix up different ohm load subs, they will recieve different amounts of powerif you had 2 d2 wired to 2ohm and a single d4 wired to 2 ohm then the d4 would get the same power as the pair of the d2's

i believe that is how it works but i have been wrong before.

~Magick_Man~

im not to sure either but i thought the amp see's only the final ohm and distributes the power evenly to each VC

somone who knows please post ... good thing to know for the future //content.invisioncic.com/y282845/emoticons/wink.gif.608e3ea05f1a9f98611af0861652f8fb.gif

 

[~Magick_Man~ 10+ year member]

im not to sure either but i thought the amp see's only the final ohm and distributes the power evenly to each VC
somone who knows please post ... good thing to know for the future //content.invisioncic.com/y282845/emoticons/wink.gif.608e3ea05f1a9f98611af0861652f8fb.gif

well the amp does only see the final ohm load but if you have 2 d2 and a single d4

it would see 1/4 ohms.

with the 2 d2 wired to 2 ohms and the d4 wired to 2 ohms the power would be split evenly between the d4 and the 2 d2's.

so say your amp puts out 1000 watts at 1 ohms

the d4 wired to 2 ohms would get 500 watts.

and the 2 d2 wired to 2 ohms would get 250 each.

this would work but it would be less than ideal.

and again i could be wrong so if anybody knows something about this please correct me.

~Magick_Man~

 

[squeak9798 5,000+ posts]

im not to sure either but i thought the amp see's only the final ohm and distributes the power evenly to each VC
somone who knows please post ... good thing to know for the future //content.invisioncic.com/y282845/emoticons/wink.gif.608e3ea05f1a9f98611af0861652f8fb.gif

The power is distributed based on the impedance of each subwoofer. In a "typical" setup, the impedances are equal, and hence equal power distribution. In a setup where there are different impedances involved, the power distribution will not be symmetrical or even and the subwoofer(s) with the higher impedances will receive less power.

 

[iagrdshaka 5,000+ posts]

if i had a monoblock 1 ohm stable amp, i would get two dual 2 and one dual 4. that's if im doing the math correctly.

nice one //content.invisioncic.com/y282845/emoticons/banghead.gif.8606515f668c74f6de0281deb475b6fd.gif

 

[helotaxi 5,000+ posts]

V=I*R and P=I*V Those are the equations you need to know. The other thing that you need to know is that the voltage is the same in every load in a parallel wiring setup and the current is the same for every load in a series wired setup. If there is a combination of wiring break it up into sections and figure out each section.

For example if you have a 2 ohm and a 4 ohm load wired in series the final load is 6 ohms. You figure the total current using the equations above and then figure power for each load using the same equations. To make the math easy we'll assume 6W. That gives us 6V and 1A into a 6 ohm load. We can now figure out the power going to each load in the circuit. For the ohm load we get 4 W and we get 2W on the 2 ohm load.

If we now wire those loads in a parallel circuit and use the same voltage you would get 9W going to the 4 ohm load and 18W going to the 2 ohm load.