Reply to thread

Message

<blockquote data-quote="helotaxi" data-source="post: 1623421" data-attributes="member: 550915">V=I*R and P=I*V&nbsp; Those are the equations you need to know.&nbsp; The other thing that you need to know is that the voltage is the same in every load in a parallel wiring setup and the current is the same for every load in a series wired setup.&nbsp; If there is a combination of wiring break it up into sections and figure out each section.For example if you have a 2 ohm and a 4 ohm load wired in series the final load is 6 ohms.&nbsp; You figure the total current using the equations above and then figure power for each load using the same equations.&nbsp; To make the math easy we&#039;ll assume 6W.&nbsp; That gives us 6V and 1A into a 6 ohm load.&nbsp; We can now figure out the power going to each load in the circuit.&nbsp; For the ohm load we get 4 W and we get 2W on the 2 ohm load.If we now wire those loads in a parallel circuit and use the same voltage you would get 9W going to the 4 ohm load and 18W going to the 2 ohm load.</blockquote>

[QUOTE="helotaxi, post: 1623421, member: 550915"] V=I*R and P=I*V Those are the equations you need to know. The other thing that you need to know is that the voltage is the same in every load in a parallel wiring setup and the current is the same for every load in a series wired setup. If there is a combination of wiring break it up into sections and figure out each section. For example if you have a 2 ohm and a 4 ohm load wired in series the final load is 6 ohms. You figure the total current using the equations above and then figure power for each load using the same equations. To make the math easy we'll assume 6W. That gives us 6V and 1A into a 6 ohm load. We can now figure out the power going to each load in the circuit. For the ohm load we get 4 W and we get 2W on the 2 ohm load. If we now wire those loads in a parallel circuit and use the same voltage you would get 9W going to the 4 ohm load and 18W going to the 2 ohm load. [/QUOTE]

Verification