Hundreth
10+ year member
CarAudio.com Elite
I don't know what class this is for, but I learned how to solve problems like that in one of my Computer Science classes, its called a linear homogeneous recurrence of degree k with constant coefficients...
Let Pn denote the amount in the RRSP after n years..
We can derive the following recurrence relation:
Pn = Pn-1 + .12Pn-1 = 1.12Pn-1
The initial condition is P = 5000
Then we have:
Pn = 1.12Pn-1 = (1.12)^nP0
We now have a formula to calculate Pn for any natural number n and can avoid the iteration.
So... P46 = (1.12)^46 * 5000 = 918330
Take 30% of that and you have 275499, subtract it from the above solution and you end up with... $642,831.00
Hope I'm right and hope that helped. //content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif
Let Pn denote the amount in the RRSP after n years..
We can derive the following recurrence relation:
Pn = Pn-1 + .12Pn-1 = 1.12Pn-1
The initial condition is P = 5000
Then we have:
Pn = 1.12Pn-1 = (1.12)^nP0
We now have a formula to calculate Pn for any natural number n and can avoid the iteration.
So... P46 = (1.12)^46 * 5000 = 918330
Take 30% of that and you have 275499, subtract it from the above solution and you end up with... $642,831.00
Hope I'm right and hope that helped. //content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif