fiberglassing my trunk...pics!!!

[saywhat? 5,000+ posts]

he wont listen, let him realize when his enclosure sounds hollow.

 

[luv2bass 10+ year member]

after polyester putty and sanding

 

[luv2bass 10+ year member]

after polyester primer and sanding

 

[luv2bass 10+ year member]

after paint and varnish(without sanding!!!)

 

[j3bus2k3 5,000+ posts]

well it looks good but you A.) have no bracing whatsoevar, and B)have a signle port for what I would guess is 2 12"....best of luck but dont be surprised if it sounds like arse.

 

[luv2bass 10+ year member]

The End

 

[PhatTonyDeMarco 5,000+ posts]

How does it sound?..

 

[IamDeMan 5,000+ posts]

How does it sound?..

dont be surprised if it sounds like arse.

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[saywhat? 5,000+ posts]

id be more than suprised if it was pleasureable to listen to. the work looks good, but u skipped some steps.

 

[luv2bass 10+ year member]

well it looks good but you A.) have no bracing whatsoevar, and B)have a signle port for what I would guess is 2 12"....best of luck but dont be surprised if it sounds like arse.

thanks for your good words.

by the way the box is for 2 15" and the little port you see it's 6" wide=more area than 2x4".i couldn't insert bigger diameter as you can see.

 

[j3bus2k3 5,000+ posts]

6" diameter port means ~28in^2 of port vs 2 4" diameter totaling ~25in^2 of port. Either way it's still not enough for 2 12" woofers let alone 2 15" woofers....I dunno man. Like I said, the box looks trick but it just seems...off.

 

[saywhat? 5,000+ posts]

thats still only like 28 sq. in. of port... u need hell.....45-55 for two fifteens, easy

 

[Chevyaudio 5,000+ posts]

thats still only like 28 sq. in. of port... u need hell.....45-55 for two fifteens, easy

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You are going to run into some major issues with only 28 Sq in of port for 2 15s....Quick question....what subs are goin in there?

 

[saywhat? 5,000+ posts]

err... is it pi®^2? if thats the case...its like 60.... im confused. i forgot the **** equation lol. i know a 4 incher is like....12.56 so im guessing its 28, just i swear it is pi(d/2)^2

 

[j3bus2k3 5,000+ posts]

area of a cirlce=(pi)*r^2 but r=d/2 so both your equations are good grant.