Enclosure Help

[big_way32 10+ year member]

Am trying to calculate the exact cu.ft for a wedge enclosure. I tried a few different sites and got anywhere from 5.8 - 6.0 cu.ft. Since I needed the exact size I worked it out by hand myself. Here are my dimensions and what i got. Can anyone double check this for me please?

Wedge Design

Outside Dimensions

Height = 22"

Depth 1 = 10"

Depth 2 = 20"

Width = 39"

Formulas used:

Rectangle

L X W X D

Triangle

0.5 (B X H X W)

Since the design is basicly a rectangle and a triangle combination, thats how i calculated it.

I got 4.12 cu.ft for the rectangle and 2.06 cu.ft for the triangle with a gross volume of 6.18 cu.ft.

I also took into account that the 1.5" (0.75" + 0.75") thickness of wood that "attach" the triangle to the retangle along the length was removed and added volume to the enclosure.

Does this sound right? Thanks

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[mig139]

Wih .75 for wood, I got 5.8!?

 

[subzero 5,000+ posts]

http://www.rockfordfosgate.com/rftech/box_wizard.asp

try this dude

comes out to 6.0 cubes BEFORE displacment. Are you porting it?

 

[big_way32 10+ year member]

Yes at 30 Hz. After sub, port, bracing and my pokets for both my amps on the box(displacement) am looking at 4 cu.ft @ 30 Hz for a Fi Q 15". If i dont like the output then i will more than likely go with a IA Death Row 15" in the same box and see how that does.