alternator question...

To find out the amperage draw on an amplifier takes its output power (RMS for average draw and total for max draw) and devide by 12. This will give a reading assuming the amp was 100% efficient. Now you have to consider that class AB amps are only about 60% efficient and class Dare about 80%. Divide the number of amps you got from the last equation by the efficiency of the amp and you should end up with a fairly accurate number.

so, amperage draw equation:

( output power / 12 ) / effeciency = amperage draw

example using a 1000 wattt class AB amplifier @ 60% efficiency

( 1000 / 12 ) / 60% = ( 83.333 ) / 60% = 138.9 Amps

 
Yes you are right. I wasn't thinking.

About 99.9999999999% of the charging systems out there are 14.4 volt

Just substitute 14.4 everywhere I said 12

so, amperage draw equation:

( output power / 14.4 ) / effeciency = amperage draw

example using a 1000 wattt class AB amplifier @ 60% efficiency

( 1000 / 14.4 ) / 60% = ( 69.444 ) / 60% = 115.74 Amps

Yeah that other number looked a little high. thanks Jmac.

I must have been thinking car=12Volt. Thats a common analogy and although not very accurate is what many people think.

 
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