Surface Area of a square actually comes to a lot more in^2 than you might realize. There is a mathmatical answer at the end so bear with me.
So the surface area of a 15" square=225 in^2, and 4 would be 900in^2 (lets assume the cones go to the edge to make it easier).
An 18" square is 324in^2 and 2 would be 648in^2.
4 15" square subs have 252in^2 more surface area. So 4 15" subs vs. 2 18" subs is a diffrence in surface area by about 28%. Considering surface area only, it is safe to say you would be about 28% louder with 4 15's, but that is with the same amount of amplifier power going to both.
On to amplifier power. The L7's are rated at 1000 watts RMS, so lets say you give 4 of them 5,000 RMS total. The X's can take 5000 RMS each so go ahead and give them 10,000 watts RMS. We know that doubling the amplifier power alone is an increase of 3db. So therefore if we assume all else is the same (surface area included even though in this situation we know it's not, but I will get to that), then the X's are going to be 3db louder.
So we go back and look at the surface area difference, to combine 2 of the biggest factors in trying to play loud (surface area and amplifier power), granted there are other variables that can and will affect your setup. There is 28% less surface area if you go with the 18's so subtract 28% for surface area. I am not sure that surface area is the same db ratio as amplifier power as it increases but for this example if we say yes, then 28% would equal .84db (3db x 28%).
In conclusion, this would leave the 2 18" X's about 2db louder than the 4 15" L7's based on my hypothesis. So you said your goal was SPL, then my suggestion would be the 2 18" Solo X's.