2 same DVC subs in parallel, but on in serie. ( 2+8ohm=2ohms) in paralel??? well it..

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2+8ohms=10ohms, divided by number of subs(2) = 5, divided by parallel (2) = 2.5

did i do that right? o will, i can always check it one the ohm meter.2.5 should give me like 1000 watts or so.

subs are dvc. each with 4 ohm loads, so one can be in series and the other in parallel and wier the subs togeter in parallel.

yall think this well work the way i want it too??? (even distrabution of power to both subs)?

 
errr what the hell you doin? its figured this way top part is 2*8=16 divide that by 2+8 which is 10- 16/10...... 1.6 ohms but why you mixxin subs?

 
Originally posted by audiolife that is still mixxing and the higher impedence woofer would be loudest
Lowest impedance woofer would be the loudest... //content.invisioncic.com/y282845/emoticons/wink.gif.608e3ea05f1a9f98611af0861652f8fb.gif

 
Originally posted by audiolife depends on if its series or parallel and i thought the same thing till richard clark did the run down lol
Branch circuitry can be easily calculated, but given the question, and how he is wiring it, the 2 ohm will take the brunt of the applied energy...

 
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