wiring help

hmm just do it at 1 ohm. wire all the positives on one line and then all the negatives on the other and plug positive and negative where they go on the amp

 
its a profile ap2000 2 channel amp, 2 kicker cvrs 4 ohms dual voice coil.

amp:

its a profile ap2000 2 channel amp, 2 kicker cvrs 4 ohms dual voice coil.

subs:

12" subwoofer with dual 4-ohm voice coils

power handling: 50-400 watts RMS (200 watts per coil)

800 watts peak power handling

 
Yeah, I've installed plenty of those.

It's 2 ohm Stable.... ALL DAY, still gets kinda warm though!

INFO:

Since it's Dual 4s, they can be wired down to 2 ohms each. Or wired up to 8 ohms each.

Soo, to get 2 ohms at the amp do this -

Wire each subs to 8 ohm, and bridge both together @ the amp for 2 ohm load.

* 8/2 = 4 , then bridge at the amp is 2. Which makes it 2 ohm.

Go to http://www.kicker.com and look @ the manual for the 12" CVR. it'll show you how to wire it to 8 ohm. I forgot which ones you connect and run down... The voice coil with the dots or the one's with the solid color....

 
Yeah, I've installed plenty of those.
It's 2 ohm Stable.... ALL DAY, still gets kinda warm though!

INFO:

Since it's Dual 4s, they can be wired down to 2 ohms each. Or wired up to 8 ohms each.

Soo, to get 2 ohms at the amp do this -

Wire each subs to 8 ohm, and bridge both together @ the amp for 2 ohm load.

* 8/2 = 4 , then bridge at the amp is 2. Which makes it 2 ohm.

Go to http://www.kicker.com and look @ the manual for the 12" CVR. it'll show you how to wire it to 8 ohm. I forgot which ones you connect and run down... The voice coil with the dots or the one's with the solid color....
please explain this further

 
Hmmm... the (2) 8ohms brought down to the amp for a 2 ohm load?

Simple:

* 8 ohm Sub * ----------- * 8 ohm Sub *

_________Tied Together__________

* 8 Divided by 2 = 4 * - Which now indicates that you have a 4 ohm load

_________ Bridging your Subs at the amp _________

* The amp is INTERNALLY Bridged which now makes you 4 ohm load to a 2 ohm load

( 4 Divided by 2 = 2 ) Which now introduces your 2 ohm load.

 
Hmmm... the (2) 8ohms brought down to the amp for a 2 ohm load?
Simple:

* 8 ohm Sub * ----------- * 8 ohm Sub *

_________Tied Together__________

* 8 Divided by 2 = 4 * - Which now indicates that you have a 4 ohm load

_________ Bridging your Subs at the amp _________

* The amp is INTERNALLY Bridged which now makes you 4 ohm load to a 2 ohm load

 

( 4 Divided by 2 = 2 ) Which now introduces your 2 ohm load.
this part makes no sense at all....a 4 ohm load is a 4 ohm load....end of story ..just by connecting it to the amp does not change impedence..

....its not bridged internally....thats why it a 2 channel amp and secondly all you have to do is wire each sub to 2 ohms and conect one sub to each channel. the amp claims 400+ x 2@2ohms

you are making this alot harder than it has to be and beside even if your math is right, which its not, that amp is only 4 ohm stable in bridged mode

 
So you're tellin' me if you tied in (2) 4ohm subs.... It's not goin' to give you a 2 ohm load @ your amp?? How is my math incorrect?

I've been installing systems for a LONG time, I know exactly what I'm talkin' about.

 
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