Wiring 3 Subs In Series And Parallel

[Tehgregzor 10+ year member]

Exactly the reason I want to. I have 3 cheap subs sitting here, and a cheap amp. I was just trying to see if anyone had an idea of how it would work before I try it. I'm just bored with all the common configurations, and wanted to try something different.

I'm bored with having hands attached to my wrists. Yeah, it works perfectly, and its been tried and tested thousands of times...but you know, i got these extra two feet lying around...i think i'll cut off my hands and attach my feet to my wrists. I'm bored with common configurations, i want to try something different.

 

[oxsign 5,000+ posts]

He's more than likely still gonna do it in his efforts to be different. The next post we'll see will be something like "why are my subs acting weird" or "what happed to my sub."

I'm bored with having hands attached to my wrists. Yeah, it works perfectly, and its been tried and tested thousands of times...but you know, i got these extra two feet lying around...i think i'll cut off my hands and attach my feet to my wrists. I'm bored with common configurations, i want to try something different.

//content.invisioncic.com/y282845/emoticons/laugh.gif.48439b2acf2cfca21620f01e7f77d1e4.gif

 

[trebor 10+ year member]

Your on the right track, just keep the subs in seperate enclosures.

Although not the optimum configuration, there's no reason it won't work and can't sound good, one of the subs will be simply getting more power......big whoop. //content.invisioncic.com/y282845/emoticons/rolleyes.gif.c1fef805e9d1464d377451cd5bc18bfb.gif

Edit: I just looked back at your diagram, wiring that way will give you a 2.66 Ohm (not 1.66) load if all your drivers are 4 Ohm.

R=resistance

(R1xR2)/(R1+R2)=R3

so... (8x4)/(8+4)=2.6666

If you paralleled two drivers then series the third you could get a 1.333 Ohm load.

 

[thch 10+ year member]

what math are you guys using? what picture are you looking at?

The correct answer is 6ohm, as previously posted. I'm just wondering what rational is being used to get 1.6 ohm, 1.3ohm, ect.. from the picture of one woofer in series with two woofers in parallel.

 

[trebor 10+ year member]

what math are you guys using? what picture are you looking at?
The correct answer is 6ohm, as previously posted. I'm just wondering what rational is being used to get 1.6 ohm, 1.3ohm, ect.. from the picture of one woofer in series with two woofers in parallel.

12ohm is possible, but not 6ohm.

I just posted the equation. Here's a good write up on the subject...

http://www.termpro.com/articles/spkrz.html

 

[thch 10+ year member]

from my previous post:

combinations where all speaker receive same power:

series: 4 + 4 + 4 = 12 ohm

parallel: 4/3 = 4/3 ohm

combinations where all speakers receive power:

1 in series with 2 in parallel: 4 + 4/2 = 6 ohm (series woofer receives 4x power)

1 in parallel with 2 in series: 1/( 1/(4+4) + 1/4) = 8/3 ohm (parallel woofer receives 4x power)

combinations where one speaker receives no power (eg, terminals shorted or left open)

2 in series: 4+4 = 8ohm

2 in parallel: 4/2 = 2ohm

combinations where two speakers receive no power

1 speaker: 4 = 4ohm

combinations where 0 speakers recieve power

short: 0 ohm

open: inf ohm.

of these, none are 1.6ohm. the 8/3 Ohm result trebor lists is correct for 1 4ohm woofer in parallel with 2 4ohm woofers in series. The picture in post 1 does not show that.

A fast counter example is that a 4ohm speaker IN SERIES with any positive resistance will be at least 4ohm. to get less would require negative resistance, which is not possible given the constraint that all speakers are 4ohm fixed resistance equivalents.

 

[Saint211 10+ year member]

I agree. I dont know where the hell you guys are getting figures other than 6 ohms. Maybe you havent really had to do any hands on work with it, or havent ever worked out a circuit on paper.

But you figure the parallel drivers first. Which comes to 2 ohms.... then 2 ohms in series with a 4 ohm driver is 6 ohms.

Really pretty simple. Even if you had a parallel connection with 20 drivers sticking off to the side of the diagram youd figure them all using the formula for parallel.. then add 4 to it

 

[trebor 10+ year member]

Didn't look close enough at the diagram and totally broke it down backwards (admitedly never considered that series option), it's 6ohm.

So we're all on the same page....

series all 3 = 12ohm

parallel 2 and series 1 = 6ohm

series2 and parallel 1 = 2.666ohm

parallel all 3 = 1.33ohm