Trig help someone!

here are a few more for the lonely

y = -sec (x-2/pie) + 2

y=2 cos (3x - 3pie/4) + 1

y = cot (x + pie/3) - 2

y = -2 tan (1/2x - pie/4) +1

y= -3 cos (2x-pie) + 1
i do remember that tan graphs are simular to sin graphs but fliped 90 deg and cot is the opposite of tan and incase you didnt know cos and sec are opposite eachother as well

 
you should read the question, it doens't seem to hard, really its pattern matching.

K * TRIGFUNC( (2pi/T)t - Phi ) + Vert

K -- amplitude

T -- period

Phi -- phase (you may want to "bound" the phase, force it be be between -pi and pi)

Vert -- vertical offset (aka DC offset)

* might be + Phi.

now for csc, tan, ctn, sec, you may need to put amplitude as inf, as these all have asymtotes.

graphing is also equally easy. CSC is 1/COS. so any point COS = 0, CSC = inf and -inf (an asymtote). if COS = 1, CSC = 1.

 
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