Since we are on the subject of ports...

[Immacomputer 10+ year member]

How about you do some measurements instead of us doing your work? I read through your description and patent and it sounds very basic. Who paid for that patent? What advantage does this have over a standard Helmholtz resonator?

Why don't you take some measurements to find the actual tuning frequency and then vary the height of the outside tube and see how it affects the measurements. Try to single out one variable at a time and work backwards to find a way to calculate and measure it. Making an electrical equivalent circuit would also help aid in pointing you in the right direction.

It's your patent; you do the work. I know that I wouldn't be doing jack shit as far as helping you along the way unless I share in the patent.

 

[BrianChia 10+ year member]

Does this mean that no one here can calculate it?

No, I'm not trying to be a dick, but I just think that no one here really cares.

 

[Hecta G 10+ year member]

Yeah, thanks..

Figured that much...

 

[Hecta G 10+ year member]

Just asking to be lead in the right direction. Not asking anyone do to anything for me.

 

[Hintzyboy 5,000+ posts]

It really shouldn't be too difficult. If my brain is working right, it's just basic trig. as long as this equation works out (A=area)

Ainner port = Aouter port-Ainner port

If that works out, then it's just a basic linear measurement. You just have to find the right size ports to make that work.

just as an example. For that design to work with a two inch inner port, you would have to use a 2.8" outer port. Then it would work like a standard cylindrical port, but it would take up less space outside the box.

If that's not what you're going for, then IDK. I know nothing about horns or any of that kind of stuff.

 

[Hecta G 10+ year member]

Thanks Hintz,

Yeah I've done that and don't know much about horns myself. I have the basic difference in area and volume but trying to figure out the effect of each change in area.

I am assuming treating the first entry (small-large) as if it was a straight port, then taking the smaller port and it's length as if coming out of the enclosure. I may not even be describing this correctly.

I may just incorporate it into my next box and see what happens.

I think I just may post my build as i get to it. I'm sure there are a few here that could use a few giggles.

 

[DarkFox 10+ year member]

yeah I was gonna say, this isn't anything new, just a diff way to do it. when people take a slot port and double it back on itself to get the length in a short enclosure, this is the SAME EXACT THING. just got to get it so you are left with the same area in the larger diameter, after you subtract the smaller diameter tube.... port length vs area calculations should work exactly the same.

 

[Hecta G 10+ year member]

Thanks Fox,

It just hit with what you were saying. I was assuming on 2 different areas, but I think what you stated make them equal.

The difference between the larger and the smaller should equal the smaller. Let me know if that's what you are talking about.

Thanks!!!

 

[James Bang 5,000+ posts]

I'd actually like to see this implemented.

I'd round out the outer/larger tube.

 

[whizdumb 10+ year member]

Wow that is a really cool idea. I never would have thought of that...

Great for when you need a long port length but your box isn't deep enough. But how do you secure the outer tube?

Trying to figure out port length I think it would be a lot easier if each tube had the same effective volume. The one you described has the outer port being roughly 9.42 square inches while the inside port is only about 3.14 sq. in (not counting for tube thicknesses). Then you could just add up the effective lengths (adding some more for end correction) and you would have a pretty close approximation.

But yeah what you would probably have to do is build it and test to find out what the actual tuning is and go from there.

 

[Immacomputer 10+ year member]

But it won't act completely like a ported enclosure as the mass of air in the outer tube will have its own point of resonance as will the inner port tube. I would bet that the distance away from the inner tube opening will have just as much of an effect as changing the length of either tube.

 

[savagebee 10+ year member]

x2, I mean, wouldnt you also have to factor in the end correction that the inner and outer ports would cause where they sepearate?

I have no idea how that would even be possible

 

[djman37 5,000+ posts]

what about when the green cylinder slides back far enough to become an enclosure itself? it looks like tuning wouldn't really change as the 'port length' doesn't really change unless you cut the green.