Since we are on the subject of ports...

[Hecta G 10+ year member]

In the rendering below, I have done a cutaway for easier viewing and explaining. The port is behind a 3/4" MDF. The outer tube is open on one end and has an OD of 4".

The inside tube has an OD of 2", both with a wall thickness of 1/16". Each tube is 6" long, and the arrows show the direction of air travel.

My question is how can you calculate effective port length when comparing to standard cylindrical ports?

Click to read more...

 

[Cravingbass123]

wtf???????????????????????????

why?

 

[mrbomb 10+ year member]

interesting

 

[matrxx dude 5,000+ posts]

diffferent size ends.

 

[matrxx dude 5,000+ posts]

crazy shit

 

[Hecta G 10+ year member]

Actually, it was something that I patented several years ago, and since I was young, had a crazy idea, built a prototype and actually worked.

My problem was why it worked. Until now I haven't wondered too much about it but with some of the guys here really REALLY know more about acoustics than I do. I approached from a mechanical side and was wondering if someone here could explain it to me.

I'm thinking about building some more to test and see if it makes any sense still.

 

[BrianChia 10+ year member]

It's not really anything that new; take a look at bullhorns--they are a concentric folded horn, just like this but with exponentially increasing flare and loaded from the other end. But I have never seen this concept applied to ports.

 

[twisztdauthorit 10+ year member]

interesting design, aslong as the airflow is smooth, i don't see why it wouldn't work. as for calculating it, well thats not my cup of tea.

 

[Immacomputer 10+ year member]

So wait, you paid for a patent on something you don't understand and don't know how to design. Wow...

 

[Hecta G 10+ year member]

So wait, you paid for a patent on something you don't understand and don't know how to design. Wow...

Your helpful...

as usual...

 

[Immacomputer 10+ year member]

What's the patent number?

 

[Hecta G 10+ year member]

What's the patent number?

5406637

 

[loudaccent 10+ year member]

i took a look for the hell of it here it is

http://patft.uspto.gov/netacgi/nph-Parser?Sect1=PTO1&Sect2=HITOFF&d=PALL&p=1&u=%2Fnetahtml%2FPTO%2Fsrchnum.htm&r=1&f=G&l=50&s1=5406637.PN.&OS=PN/5406637&RS=PN/5406637

 

[SilverSquared 10+ year member]

in the images there, WOW...I'll buy 4

 

[Hecta G 10+ year member]

Does this mean that no one here can calculate it?