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Engineering Student
(Where Sd = surface area of cone?)Vd = Sd x Xmax
Sd = 3.372^2 * 3.14 = 35.76
Xmax = 0.45 inches
Vd = 35.76 * 0.45 = 16.092
Now, as soon as I try to calculate required port area, with tuning of 35hz
dV = 39.37 * (35*16.092) ^ 0.5dV>/= 39.37*(Fb*Vd)^0.5
= 39.37 * 23.73
= 934 sq inches of port area ??