Most Wattage

[linksyz 10+ year member]

how many amps and batteries would one need to get 20kw ?!!?!?

 

[kickerlivinloud 10+ year member]

4 JBL clowns could do it. Or a couple Zapco 9.0's. You would need a lot more than jsut batterys. Probably dual alts of 300amp+. IDK, talking about some serious power here!!

Jon

 

[linksyz 10+ year member]

4 JBL clowns could do it. Or a couple Zapco 9.0's. You would need a lot more than jsut batterys. Probably dual alts of 300amp+. IDK, talking about some serious power here!!


Jon

****... i wonder how the hell did car stay in 1 piece (if it did) for those few burps. this is off topic.. but does anybody have price list for iraggi alts?

 

[qtipextra 5,000+ posts]

I cant find any info on TRF, MT, or IA DP. And also, some subs metioned eirlier, I looked on the site, only took like 1600 w, so when it took a 32kw burp, it blew it, right? and if not it was highly distorted?

 

[Mark_ab 5,000+ posts]

B15. Wired to 1ohm. To a 110V socket. 60hz. Took it like a champ.

 

[Bumpin' Yota 10+ year member]

110^2/1 = 12,100 watts ...

wrong. impeadance changes radically with movement of the coil.

The typical outlet is fused/breakered at 15 ampres. So:

P = VI

P = (120vac)(15a)

P = 1800 watts.

Even if the outlet were stable to 30 ampres:

P = (120vac)(30a)

P = 3600 watts.

 

[Bumpin' Yota 10+ year member]

how many amps and batteries would one need to get 20kw ?!!?!?

Easier than you think actaully. 8 modified mtx 1501d's running at 17.5v dc and with a DCR of 0.7 each. Under those conditions at 47hz, each 1501d was generating ~2600watts. (5200watts a coil x 4 coils.) That's why you used to see mtx in a LOT of ss and extreme vehicles in the drag lanes.

Even a single JBL crown 6kw will hit 10kw with a little modding.

Zapco 9.0s? You are going to need 7 of em to break over 20kw.

All of the above are going to need GOOD voltage supplys, so as many batteries as you can afford.

 

[qtipextra 5,000+ posts]

wrong. impeadance changes radically with movement of the coil.
The typical outlet is fused/breakered at 15 ampres. So:

P = VI

P = (120vac)(15a)

P = 1800 watts.

Even if the outlet were stable to 30 ampres:

P = (120vac)(30a)

P = 3600 watts.

Wrong again' date=' sorry to tell you. It equals volts, not watts. tho I dont know how to convert, i know they ARE not the same thing! Volts is a measure of steady power, wereas watts is a measures of how much work can be done.

P = VI

P = (120vac)(15a)

P = 1800 [b']VOLTS!![/b]

P = (120vac)(30a)

P = 3600 VOLTS!!

 

[Acidburn 5,000+ posts]

Wrong again, sorry to tell you. It equals volts, not watts. tho I dont know how to convert, i know they ARE not the same thing! Volts is a measure of steady power, wereas watts is a measures of how much work can be done.
P = VI

P = (120vac)(15a)

P = 1800 VOLTS!!

P = (120vac)(30a)

P = 3600 VOLTS!!

uhhh.. you're wrong, Power(watts) = Voltage(volts) x Current(amps)

 

[monte_carlo97 10+ year member]

Easier than you think actaully. 8 modified mtx 1501d's running at 17.5v dc and with a DCR of 0.7 each. Under those conditions at 47hz' date=' each 1501d was generating ~2600watts. (5200watts a coil x 4 coils.) That's why you used to see mtx in a LOT of ss and extreme vehicles in the drag lanes.
Even a single JBL crown 6kw will hit 10kw with a little modding.

Zapco 9.0s? You are going to need 7 of em to break over 20kw.

All of the above are going to need GOOD voltage supplys, so as many batteries as you can afford.[/quote']

How do you mod an amp? Soldering chips?

BTW a 12" pyle took a welder for about .5 seconds. The welder was set to 300 amps.

 

[denim 5,000+ posts]

APX's have taken well over 16,000 but I am not sure the number

 

[qtipextra 5,000+ posts]

Yea, sorry yo. I had my equation varibles mixed up.

 

[Bumpin' Yota 10+ year member]

Wrong again, sorry to tell you. It equals volts, not watts. tho I dont know how to convert, i know they ARE not the same thing! Volts is a measure of steady power, wereas watts is a measures of how much work can be done.
P = VI

P = (120vac)(15a)

P = 1800 VOLTS!!

P = (120vac)(30a)

P = 3600 VOLTS!!

Not quite, but I'm glad you see that now. To elaborate a bit more let me demonstrate EXACTLY what a volt and watt are, and use a proof to demonstrate! //content.invisioncic.com/y282845/emoticons/biggrin.gif.d71a5d36fcbab170f2364c9f2e3946cb.gif

1 volt = [1(kg)(meter^2)] / [(second^3)(ampere)]

1 watt = 1 joule / second

1 watt = (1 Newton)(meter) / second

1 watt = [1 kg/(second^2)] (meter) / second

simplifying we find:

1 watt = [1(kg)(meter)] / (second ^3)

therefore:

P = (I)(V)

1 watt = (1 volt)(1ampere)

1 watt = ( [1(kg)(meter^2)] / [(second^3)(ampere)] )(1 ampere)

1 watt = [1(kg)(meter^2)] / (second^3)

And that is WHY Power is in the SI units of Watts. //content.invisioncic.com/y282845/emoticons/biggrin.gif.d71a5d36fcbab170f2364c9f2e3946cb.gif enjoy!

 

[InhumanAcura 5,000+ posts]

Not quite' date=' but I'm glad you see that now. To elaborate a bit more let me demonstrate EXACTLY what a volt and watt are, and use a proof to demonstrate! //content.invisioncic.com/y282845/emoticons/biggrin.gif.d71a5d36fcbab170f2364c9f2e3946cb.gif
1 volt = [1(kg)(meter^2)'] / [(second^3)(ampere)]

1 watt = 1 joule / second

1 watt = (1 Newton)(meter) / second

1 watt = [1 kg/(second^2)] (meter) / second

simplifying we find:

1 watt = [1(kg)(meter)] / (second ^3)

therefore:

P = (I)(V)

1 watt = (1 volt)(1ampere)

1 watt = ( [1(kg)(meter^2)] / [(second^3)(ampere)] )(1 ampere)

1 watt = [1(kg)(meter^2)] / (second^3)

And that is WHY Power is in the SI units of Watts. //content.invisioncic.com/y282845/emoticons/biggrin.gif.d71a5d36fcbab170f2364c9f2e3946cb.gif enjoy!

Wrong...j/k

 

[geolemon 10+ year member]

Who cares how many watts any subwoofer can take?

If I've got a sub that can "take" 20,000 watts continuous... and it's only just as loud as anything else out there, I'm going to feel like a bit of a sucker....

On the other hand, how fun is it to build a system that creates roof flex and turns the rear window into mild jello with just 400w?

IMO, it's not about power (needing power, and wanting power are two different things... the former sucks, but you've got reasons at least).. it's about output... dB.. SPL. :boobies:

And IMO, power is the wrong place to look - at least first - if you are looking for ways to improve output. Even in the most idealistic sense, the relation of power to output isn't proportional... it takes a 4x increase in power to effect only a 2x increase in output - and in reality, it's worse, when you factor in things like heat and power compression.

And let's not forget all the additional money you'll need to spend to actually get the car to be able to produce the current that the amps need to make that much power! //content.invisioncic.com/y282845/emoticons/wink.gif.608e3ea05f1a9f98611af0861652f8fb.gif

IMO, I wouldn't look to change my power level until after I've exhausted my other, more efficient variables. (keyword: efficient... efficiency... hint hint //content.invisioncic.com/y282845/emoticons/wink.gif.608e3ea05f1a9f98611af0861652f8fb.gif )