I'm being told you CANT wire three DVC 4 ohm kicker woofers into a 1.33 ohm load. Check me on this, but I am 99.999% sure I am right.
If you take two subs, wire their voice coils in series, each sub is effectively 8 ohms (4 + 4 = 8) (That is two woofers at 8 ohms each)
If you take those two subs and wire them in parallel, the total impedance is 4 ohms for the pair (1/8 + 1/8 = 1/4) (That is TWO 8 ohm woofers wired in parallel, 4 ohms total now... ONE 4 ohm pair of DVC woofers)
If you take the last sub, wire its coils in parallel, you get (1/4 + 1/4 = 1/2) so it is at two ohms. That is ONE 2 ohm sub. Two 4 ohm coils... one 2 ohm pair. Then wire the sub at 2 ohms in with the other pair at 4 ohms so you get (1/4 + 1/2 = 1/(3/2)) or 1.3333 ohms.
Correct, yes?
If you take two subs, wire their voice coils in series, each sub is effectively 8 ohms (4 + 4 = 8) (That is two woofers at 8 ohms each)
If you take those two subs and wire them in parallel, the total impedance is 4 ohms for the pair (1/8 + 1/8 = 1/4) (That is TWO 8 ohm woofers wired in parallel, 4 ohms total now... ONE 4 ohm pair of DVC woofers)
If you take the last sub, wire its coils in parallel, you get (1/4 + 1/4 = 1/2) so it is at two ohms. That is ONE 2 ohm sub. Two 4 ohm coils... one 2 ohm pair. Then wire the sub at 2 ohms in with the other pair at 4 ohms so you get (1/4 + 1/2 = 1/(3/2)) or 1.3333 ohms.
Correct, yes?