DBfan187
5,000+ posts
Supa's mom was here!
around 7"
mapolley07
10+ year member
its all imaginary
port length is different from port area. Port area is just the flat area of the port hole. I think you are looking for volume?
port area would be 28.274 sq. inches
volume would be 113.097 cubic inches
port area would be 28.274 sq. inches
volume would be 113.097 cubic inches
mapolley07
10+ year member
its all imaginary
what the hell are you talking about?
wrong!!!! you used diameter instead of radius
port area would be 7.065 sq in
volume would be 28.26 cu in
area = pi x r sq.
volume = pi x r sq x h
What the hell are YOU talking about?
DBfan187
5,000+ posts
Supa's mom was here!
//content.invisioncic.com/y282845/emoticons/confused.gif.e820e0216602db4765798ac39d28caa9.gif LET ME GUESS, YOU FAILED THE READING COMPREHENSION TEST ?
yeah.. about 7" is right.. Not exact...
also, you need to know the xmax of your driver to find out how much port area minimum you need for it, and you will also want to know the size of the box..
also, you need to know the xmax of your driver to find out how much port area minimum you need for it, and you will also want to know the size of the box..
helotaxi
5,000+ posts
Kilroy was Here
For a more realistic estimation of area needed, you need to consider the actual power being used not the Xmax. Port velocity is highest where cone movement is almost zero. Xmax doesn't matter. Tuning, power and box volume all come into play, Xmax does not. The flare in the aeroport also greatly reduces the port velocity allowing you to use a smaller port than you would need without the flare.
Speedbump3
Banned
Idiot
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