DVC more output than SVC?

simon21
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Let's say that I have 2 of the same subs. One is Dual 2 ohm and the other is single 4 ohm. If I run the 2 ohm one in series and give it 200W at 4 ohms, will it have more output than if I run the single voice coil one with 200W at 4 ohms? (EVERYTHING else being equal)

If I run the DVC one in series and give it 200W, then each voice coil will see 200W, making a total of 400W, so I would think that it will give more output at the same power.

 
Let's say that I have 2 of the same subs. One is Dual 2 ohm and the other is single 4 ohm. If I run the 2 ohm one in series and give it 200W at 4 ohms, will it have more output than if I run the single voice coil one with 200W at 4 ohms? (EVERYTHING else being equal)If I run the DVC one in series and give it 200W, then each voice coil will see 200W, making a total of 400W, so I would think that it will give more output at the same power.
No, if you run the dual 2 with 200w @4, all it will see is 200w. The same as if you give the svc 200w. 200w will still be 200w. The dvc will just give you different wiring options. Using two coils can't make your amp put out twice the power.

 
If I run two 2 ohm subs in series for a total of 4 ohms and give it 200W, then each sub will see 200W. It will be the same thing as having two 4 ohm subs and running them with a 2 channel 400W amp. So I guess that's not how DVC works.

 
If I run two 2 ohm subs in series for a total of 4 ohms and give it 200W, then each sub will see 200W.
No, the subs will share the 200w. So each sub will get~100w. If you're getting 200w from your amp, thats all you're going to get. Hooking up two subs isn't going to make it put out 400w somehow. It can't double it's output by you hooking up more subs. The same with dvc. Just because you have two coils won't make your amp double it's output. Maybe I'm not understanding you right?

 
If 2 subs are connected in series, it means that the electricity will go into the first one, come out and go into the second one, then back to the amp. The same electricity passes through each one. If the first sees 200W, the same electricity will then pass to the second sub. Even though the amp is putting out 200W total, each sub will see that 200W.

 
If 2 subs are connected in series, it means that the electricity will go into the first one, come out and go into the second one, then back to the amp. The same electricity passes through each one. If the first sees 200W, the same electricity will then pass to the second sub. Even though the amp is putting out 200W total, each sub will see that 200W.
Um, no. You lack a basic understanding of circuits. The equations you need to concern yourself with are V=IR and P=VI. To figure the power at each sub, you need to first understand what is common among the loads in various wiring layouts. In a parallel circuit, the voltage is the same on all loads in the circuit and the current is figured based on each individual load and the voltage using the first equation above. The total circuit current is the sum of all the individual currents and the total power is the sum of the currents multiplied by the common voltage.

A series circuit has all the currents equal and the voltage drops vary with the resistance of each load. To calculate the power and voltage for each load you need to know the total voltage and the total resistance for the circuit and solve for current. From there you solve each load for voltage drop and using the constant current solve for power.

I'll use 400W to make the math easy for the example:

400W total in a 4 ohm load gives us 40V and 10A. In a series circuit that 10A goes through each load. Based on the first equation 10A through 2 ohms gives us a voltage drop of 20V. 20V*10A=200W per driver. Add the 2 drivers together to get our total of 400W.

A parallel circuit would yield the same type result. Using 8 ohm drivers to keep the math easy with our 400W you would get a constant voltage of 40V on each load. That gives us 5A of current and 200W on each driver. Add the currents for the total of 10A and the powers for 400W.

 
Good post

I'll simplify it a bit. Each speaker acts as a resistor. Resistors "absorb" power (or rather voltage). In the case of the speaker, the power is absorbed and turned into mechanical energy. The power not absorbed in a series circuit is then passed on to the next resistor where the same thing happens.

To the OP, what you're describing in your post is a superconductive, infinite power circuit, with zero loss potential. We'll probably see that type of circuit on equipment used to colonize the far reaches of the universe. In other words, by today's science, it's absolutely impossible.

 
He's just insecure because the "Class of 2006" has proven themselves repeatedly to be really dumb and unable to grasp simple concepts such as "search" and not starting 5 threads about the exact same thing within 10 minutes and asking the same 3 questions over and over and over and over and...well you get the idea.

 
He's just insecure because the "Class of 2006" has proven themselves repeatedly to be really dumb and unable to grasp simple concepts such as "search" and not starting 5 threads about the exact same thing within 10 minutes and asking the same 3 questions over and over and over and over and...well you get the idea.
Hey now. I don't qualify for any of those.

 
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