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<blockquote data-quote="helotaxi" data-source="post: 2902499" data-attributes="member: 550915">Um, no.&nbsp; You lack a basic understanding of circuits.&nbsp; The equations you need to concern yourself with are V=IR and P=VI.&nbsp; To figure the power at each sub, you need to first understand what is common among the loads in various wiring layouts.&nbsp; In a parallel circuit, the voltage is the same on all loads in the circuit and the current is figured based on each individual load and the voltage using the first equation above.&nbsp; The total circuit current is the sum of all the individual currents and the total power is the sum of the currents multiplied by the common voltage.A series circuit has all the currents equal and the voltage drops vary with the resistance of each load.&nbsp; To calculate the power and voltage for each load you need to know the total voltage and the total resistance for the circuit and solve for current.&nbsp; From there you solve each load for voltage drop and using the constant current solve for power.I&#039;ll use 400W to make the math easy for the example:400W total in a 4 ohm load gives us 40V and 10A.&nbsp; In a series circuit that 10A goes through each load.&nbsp; Based on the first equation 10A through 2 ohms gives us a voltage drop of 20V.&nbsp; 20V*10A=200W per driver.&nbsp; Add the 2 drivers together to get our total of 400W.A parallel circuit would yield the same type result.&nbsp; Using 8 ohm drivers to keep the math easy with our 400W you would get a constant voltage of 40V on each load.&nbsp; That gives us 5A of current and 200W on each driver.&nbsp; Add the currents for the total of 10A and the powers for 400W.</blockquote>

[QUOTE="helotaxi, post: 2902499, member: 550915"] Um, no. You lack a basic understanding of circuits. The equations you need to concern yourself with are V=IR and P=VI. To figure the power at each sub, you need to first understand what is common among the loads in various wiring layouts. In a parallel circuit, the voltage is the same on all loads in the circuit and the current is figured based on each individual load and the voltage using the first equation above. The total circuit current is the sum of all the individual currents and the total power is the sum of the currents multiplied by the common voltage. A series circuit has all the currents equal and the voltage drops vary with the resistance of each load. To calculate the power and voltage for each load you need to know the total voltage and the total resistance for the circuit and solve for current. From there you solve each load for voltage drop and using the constant current solve for power. I'll use 400W to make the math easy for the example: 400W total in a 4 ohm load gives us 40V and 10A. In a series circuit that 10A goes through each load. Based on the first equation 10A through 2 ohms gives us a voltage drop of 20V. 20V*10A=200W per driver. Add the 2 drivers together to get our total of 400W. A parallel circuit would yield the same type result. Using 8 ohm drivers to keep the math easy with our 400W you would get a constant voltage of 40V on each load. That gives us 5A of current and 200W on each driver. Add the currents for the total of 10A and the powers for 400W. [/QUOTE]

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