solidcrowd 10+ year member
CarAudio.com Elite
To what point does the cone area make up for the lack of airspace.
Examples: (All drivers in 2.2cu.ft. enclosure @ 32hz)
1.) 1 12" = 113.10 sq.in. (2.2 per driver)
2.) 2 12" = 226.20 sq.in. (1.1 per driver)
3.) 2 10" = 157.08 sq.in. (1.1 per driver)
4.) 3 10" = 235.62 sq.in. (0.7 per driver)
5.) 3 8" = 150.81 sq.in. (0.7 per driver)
6.) 4 8" = 201.08 sq.in (0.55 per driver)
Now this MAY be subwoofer dependant, but what im trying to figure out is what would be the best application out of these 5 to move more air (make more efficient=louder) but also have enough airspace so they aren't sufforcating. Maybe there's an equation to figure this out?
Discuss
Examples: (All drivers in 2.2cu.ft. enclosure @ 32hz)
1.) 1 12" = 113.10 sq.in. (2.2 per driver)
2.) 2 12" = 226.20 sq.in. (1.1 per driver)
3.) 2 10" = 157.08 sq.in. (1.1 per driver)
4.) 3 10" = 235.62 sq.in. (0.7 per driver)
5.) 3 8" = 150.81 sq.in. (0.7 per driver)
6.) 4 8" = 201.08 sq.in (0.55 per driver)
Now this MAY be subwoofer dependant, but what im trying to figure out is what would be the best application out of these 5 to move more air (make more efficient=louder) but also have enough airspace so they aren't sufforcating. Maybe there's an equation to figure this out?
Discuss