what type of amp?
it gives 256VA out. 247W in. assuming this is DC input to amplifier, AC output of amplifier.
there will be error on each measurement due to how the signals align.
power is RMS(V * I), which is equal or less then RMS(V)*RMS(I).
an explaination of how this could make sense mathmatically would be to look at an example where a person spins around, then walks 10ft. how far east-west has the person walked? the distance the person has walked (V*A in the analogy) is equal or greater then the distance the person has traveled in the east-west directions (real power in the analogy).
as shown, this gives 103% efficiency.
this is not a correct figure, but may be explainable due to the way class D amps handel inductive loads and the mentioned issues with volt-amps vs watts.
it does give that |Z| = 2.8ohm though. IMO thats the only thing a clamp+DMM should be used for.
edit:
if you have 95% efficiency in this case you would have 235W, 102VAR, giving an estimated impedance of 2.8ohm, +27deg. if you check winISD, you might be able to determine if this is reasonable to expect such an impedance and impedance phase. keep in mind this is under the assumption that the amp is 95% efficient and the measurements are correct.