calculating enclosure volume???

here ya go ciaonzo........sealed volume to achieve a target Qtc

You may substitute any Qtc between 0.50 and 1.50 in place of 0.70 in both equations (both must have same value) to experiment with enclosure size. Qtc of 0.70 is generally considered an optimum alignment, with very good transient response, low cut-off frequency, and flattest response to the cut-off - See Qtc.

Note: You must always choose a Qtc higher than the driver's Qts!

Find alpha: X = (0.70 / Qts)^2 - 1

Then calculate enclosure volume: Vb = Vas / X

System resonant frequency: Fcb = 0.70 / Qts ( Fs)

To find the theoretical cut-off frequency, use the following chart to find the F3 factor:

Qtc

F3 Factor

Qtc

F3 Factor

0.50

= 1.55

1.00

= 0.79

0.60

= 1.21

1.10

= 0.76

0.70

= 1.0

1.20

= 0.74

0.80

= 0.9

1.30

= 0.72

0.90

= 0.83

1.40

= 0.71

Then: F3 = Fc x (F3 Factor)

 
LOL, thanks boogeyman. I already know it well but I wanted to see if the OP could expand past HxWxL=in^3/1728 for finding volume. I was hoping he would come back at me with the simple Vb = Vas / (( Qtc / Qts ) ² - 1) but he chose not to respond. I certainly do appreciate you taking the time to type all that out and it comforts me to know that some people are using the math once in a while. //content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif

 
That's what a copy of the Loudspeaker Designer's Cookbook is for.
i've got this book, best $30 I spent :-D (besides that lap dance //content.invisioncic.com/y282845/emoticons/confused.gif.e820e0216602db4765798ac39d28caa9.gif) j/k

 
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