here ya go ciaonzo........sealed volume to achieve a target Qtc
You may substitute any Qtc between 0.50 and 1.50 in place of 0.70 in both equations (both must have same value) to experiment with enclosure size. Qtc of 0.70 is generally considered an optimum alignment, with very good transient response, low cut-off frequency, and flattest response to the cut-off - See Qtc.
Note: You must always choose a Qtc higher than the driver's Qts!
Find alpha: X = (0.70 / Qts)^2 - 1
Then calculate enclosure volume: Vb = Vas / X
System resonant frequency: Fcb = 0.70 / Qts ( Fs)
To find the theoretical cut-off frequency, use the following chart to find the F3 factor:
Qtc
F3 Factor
Qtc
F3 Factor
0.50
= 1.55
1.00
= 0.79
0.60
= 1.21
1.10
= 0.76
0.70
= 1.0
1.20
= 0.74
0.80
= 0.9
1.30
= 0.72
0.90
= 0.83
1.40
= 0.71
Then: F3 = Fc x (F3 Factor)
You may substitute any Qtc between 0.50 and 1.50 in place of 0.70 in both equations (both must have same value) to experiment with enclosure size. Qtc of 0.70 is generally considered an optimum alignment, with very good transient response, low cut-off frequency, and flattest response to the cut-off - See Qtc.
Note: You must always choose a Qtc higher than the driver's Qts!
Find alpha: X = (0.70 / Qts)^2 - 1
Then calculate enclosure volume: Vb = Vas / X
System resonant frequency: Fcb = 0.70 / Qts ( Fs)
To find the theoretical cut-off frequency, use the following chart to find the F3 factor:
Qtc
F3 Factor
Qtc
F3 Factor
0.50
= 1.55
1.00
= 0.79
0.60
= 1.21
1.10
= 0.76
0.70
= 1.0
1.20
= 0.74
0.80
= 0.9
1.30
= 0.72
0.90
= 0.83
1.40
= 0.71
Then: F3 = Fc x (F3 Factor)